A desk lamp produced by The Luminar Company was found to be defective (D). There are three factories (A, B, C) where such desk lamps are manufactured. A Quality Control Manager (QCM) is responsible for investigating the source of found defects. This is what the QCM knows about the company's desk lamp production and the possible source of defects: % of total production Probability of defective lamps 0.015 = P(D|A) 0.010 = P(D| B) Factory 0.35 = P(A) B 0.35 = P(B) 0.30 = P(C) 0.020 = P(D|C) The QCM would like to answer the following question: If a randomly selected lamp is defective, what is the probability that the lamp was manufactured in factory B? P(B/D)?

A First Course in Probability (10th Edition)
10th Edition
ISBN:9780134753119
Author:Sheldon Ross
Publisher:Sheldon Ross
Chapter1: Combinatorial Analysis
Section: Chapter Questions
Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...
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A desk lamp produced by The Luminar Company was found to be defective (D). There are three factories (A, B, C) where such desk lamps are manufactured. A Quality Control Manager (QCM) is responsible for investigating the source of found defects. This is what
the QCM knows about the company's desk lamp production and the possible source of defects:
% of total production
0.35 = P(A)
Factory
Probability of defective lamps
0,015 = P(D|A)
0.35 = P(B)
0.010 = P(D| B)
0.020 = P(D|C)
B
0.30 = P(C)
The QCM would like to answer the following question: If a randomly selected lamp is defective, what is the probability that the lamp was manufactured in factory B?
P(B/D)?
Transcribed Image Text:A desk lamp produced by The Luminar Company was found to be defective (D). There are three factories (A, B, C) where such desk lamps are manufactured. A Quality Control Manager (QCM) is responsible for investigating the source of found defects. This is what the QCM knows about the company's desk lamp production and the possible source of defects: % of total production 0.35 = P(A) Factory Probability of defective lamps 0,015 = P(D|A) 0.35 = P(B) 0.010 = P(D| B) 0.020 = P(D|C) B 0.30 = P(C) The QCM would like to answer the following question: If a randomly selected lamp is defective, what is the probability that the lamp was manufactured in factory B? P(B/D)?
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