Consider the general reaction belo X₂(g) + 2Y₂(g) = 2XY₂(g) K = 3.9 x 10-8 @ 298 K 0.50 M X2 and Y2 were added to a sea vessel. Calculate the equilibrium concentrations of the components. Wha the equilibrium concentration of XY2 ?] [XY₂] = [?] x 10 M
Consider the general reaction belo X₂(g) + 2Y₂(g) = 2XY₂(g) K = 3.9 x 10-8 @ 298 K 0.50 M X2 and Y2 were added to a sea vessel. Calculate the equilibrium concentrations of the components. Wha the equilibrium concentration of XY2 ?] [XY₂] = [?] x 10 M
Chemistry
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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![**Chemical Equilibrium: Calculating Equilibrium Concentrations**
**Consider the general reaction below:**
\( \mathbf{X_2(g) + 2Y_2(g) \rightleftharpoons 2XY_2(g)} \)
**Given:**
- Equilibrium Constant, \( K = 3.9 \times 10^{-8} \) at \( 298 \, \text{K} \)
**Initial Conditions:**
- 0.50 M \( \mathbf{X_2} \) and 0.50 M \( \mathbf{Y_2} \) were added to a sealed vessel.
**Objective:**
Calculate the equilibrium concentrations of the components. What is the equilibrium concentration of \( \mathbf{XY_2} \)?
\[ [XY_2] = \boxed{?} \times 10^{\boxed{?}} \, \text{M} \]
**Steps to Solve:**
1. **Set up the ICE Table** (Initial, Change, Equilibrium) to find the equilibrium concentrations:
- **Initial Concentrations:**
\[
\begin{aligned}
[X_2] &= 0.50 \, \text{M} \\
[Y_2] &= 0.50 \, \text{M} \\
[XY_2] &= 0 \, \text{M}
\end{aligned}
\]
- **Change in Concentrations:**
\[
\begin{aligned}
[X_2] &= -x \\
[Y_2] &= -2x \\
[XY_2] &= +2x
\end{aligned}
\]
- **Equilibrium Concentrations:**
\[
\begin{aligned}
[X_2] &= 0.50 - x \\
[Y_2] &= 0.50 - 2x \\
[XY_2] &= 2x
\end{aligned}
\]
2. **Write the expression for the equilibrium constant \( K \):**
\[
K = \frac{[XY_2]^2}{[X_2][Y_2]^2}
\]
Plug in the equilibrium concentrations:
\[
3.9 \times 10](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F9e34ac62-cb87-4fee-9bdd-4f82be5e7b79%2F273cd52d-da02-4090-a886-6dfe15a5f52b%2Fkclra3v_processed.png&w=3840&q=75)
Transcribed Image Text:**Chemical Equilibrium: Calculating Equilibrium Concentrations**
**Consider the general reaction below:**
\( \mathbf{X_2(g) + 2Y_2(g) \rightleftharpoons 2XY_2(g)} \)
**Given:**
- Equilibrium Constant, \( K = 3.9 \times 10^{-8} \) at \( 298 \, \text{K} \)
**Initial Conditions:**
- 0.50 M \( \mathbf{X_2} \) and 0.50 M \( \mathbf{Y_2} \) were added to a sealed vessel.
**Objective:**
Calculate the equilibrium concentrations of the components. What is the equilibrium concentration of \( \mathbf{XY_2} \)?
\[ [XY_2] = \boxed{?} \times 10^{\boxed{?}} \, \text{M} \]
**Steps to Solve:**
1. **Set up the ICE Table** (Initial, Change, Equilibrium) to find the equilibrium concentrations:
- **Initial Concentrations:**
\[
\begin{aligned}
[X_2] &= 0.50 \, \text{M} \\
[Y_2] &= 0.50 \, \text{M} \\
[XY_2] &= 0 \, \text{M}
\end{aligned}
\]
- **Change in Concentrations:**
\[
\begin{aligned}
[X_2] &= -x \\
[Y_2] &= -2x \\
[XY_2] &= +2x
\end{aligned}
\]
- **Equilibrium Concentrations:**
\[
\begin{aligned}
[X_2] &= 0.50 - x \\
[Y_2] &= 0.50 - 2x \\
[XY_2] &= 2x
\end{aligned}
\]
2. **Write the expression for the equilibrium constant \( K \):**
\[
K = \frac{[XY_2]^2}{[X_2][Y_2]^2}
\]
Plug in the equilibrium concentrations:
\[
3.9 \times 10
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