2NO(g) + 2H₂(g) = N₂(g) + 2H₂O(g) The system initially contained 0.2500 M NO, 0.1300 M H2, and 0.2500 M H₂O. At equilibrium, the concentration of NO is 0.1296 M. What is the equilibrium concentration of H₂? [H₂] = [?] x 10¹ M K= [N₂] [H₂O]2 [NO]2[H₂]2 Coefficient (green) Exponent (yellow) Enter

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### Chemical Equilibrium Calculation: Determining Equilibrium Concentration of \( \text{H}_2 \)

**Chemical Equation:**
\[ 2\text{NO}(g) + 2\text{H}_2(g) \rightleftharpoons \text{N}_2(g) + 2\text{H}_2\text{O}(g) \]

**Initial Conditions:**
- Initial concentration of \(\text{NO}\): 0.2500 M
- Initial concentration of \(\text{H}_2\): 0.1300 M
- Initial concentration of \(\text{H}_2\text{O}\): 0.2500 M

**Equilibrium Condition:**
- Equilibrium concentration of \(\text{NO}\): 0.1296 M

**Problem Statement:**
Find the equilibrium concentration of \(\text{H}_2\).

**Given Equation:**
\[ [\text{H}_2] = [\text{?}] \times 10^{[?]} M \]
\[ K = \frac{[\text{N}_2][\text{H}_2\text{O}]^2}{[\text{NO}]^2[\text{H}_2]^2} \]

**Inputs for Calculation:**
- **Coefficient (green):** Input field for the coefficient of the concentration term.
- **Exponent (yellow):** Input field for the exponent of the concentration term.

**Instructions:**
1. Input the coefficient for the \(\text{H}_2\) concentration into the green box.
2. Input the exponent value for the \(\text{H}_2\) concentration into the yellow box.
3. Click "Enter" to submit the values.

### Explanation of Inputs and Outputs

- **Coefficient (green)**: This is a multiplication factor for the equilibrium concentration of \(\text{H}_2\).
- **Exponent (yellow)**: This reflects the power of 10 to which the concentration of \(\text{H}_2\) is raised.

Understanding and calculating these values correctly will help you determine the equilibrium concentration of hydrogen gas (\(\text{H}_2\)) in the reaction.
Transcribed Image Text:### Chemical Equilibrium Calculation: Determining Equilibrium Concentration of \( \text{H}_2 \) **Chemical Equation:** \[ 2\text{NO}(g) + 2\text{H}_2(g) \rightleftharpoons \text{N}_2(g) + 2\text{H}_2\text{O}(g) \] **Initial Conditions:** - Initial concentration of \(\text{NO}\): 0.2500 M - Initial concentration of \(\text{H}_2\): 0.1300 M - Initial concentration of \(\text{H}_2\text{O}\): 0.2500 M **Equilibrium Condition:** - Equilibrium concentration of \(\text{NO}\): 0.1296 M **Problem Statement:** Find the equilibrium concentration of \(\text{H}_2\). **Given Equation:** \[ [\text{H}_2] = [\text{?}] \times 10^{[?]} M \] \[ K = \frac{[\text{N}_2][\text{H}_2\text{O}]^2}{[\text{NO}]^2[\text{H}_2]^2} \] **Inputs for Calculation:** - **Coefficient (green):** Input field for the coefficient of the concentration term. - **Exponent (yellow):** Input field for the exponent of the concentration term. **Instructions:** 1. Input the coefficient for the \(\text{H}_2\) concentration into the green box. 2. Input the exponent value for the \(\text{H}_2\) concentration into the yellow box. 3. Click "Enter" to submit the values. ### Explanation of Inputs and Outputs - **Coefficient (green)**: This is a multiplication factor for the equilibrium concentration of \(\text{H}_2\). - **Exponent (yellow)**: This reflects the power of 10 to which the concentration of \(\text{H}_2\) is raised. Understanding and calculating these values correctly will help you determine the equilibrium concentration of hydrogen gas (\(\text{H}_2\)) in the reaction.
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