Consider the following recursive algorithm: Int active(Int lst [1.int lowerindex, Int upperindex) Int max; if (lowerindex == upperindex) return lowerlndex; else max = active(list, lowerlndex + , upperindex); if (list|lowerindex] > = max) return lowerlndex; else return mox, What is the result of: int x= active([1,5,4,3,2],0,4) Select one: a. 2 b.3

Consider the following recursive algorithm: Int active(Int lst [1.int lowerindex, Int upperindex) Int max; if (lowerindex == upperindex) return lowerlndex; else max = active(list, lowerlndex + , upperindex); if (list|lowerindex] > = max) return lowerlndex; else return mox, What is the result of: int x= active([1,5,4,3,2],0,4) Select one: a. 2 b.3

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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Use an array and two index variables. Write functions or methods push, pop, and sizeof. Then write a main function or method that will allocate the stack at n=10 and push some strings in ii, print out the size, and then pop some strings from it. Note make stack be be able to hold string variable type. java
public class Main { static int findPosSum(int A[], int N) { if (N <= 0) return 0; { if(A[N-1]>0) return (findPosSum(A, N - 1) + A[N - 1]); else return findPosSum(A, N - 1); } } public static void main(String[] args) { int demo[] = { 11, -22, 33, -4, 25,12 }; System.out.println(findPosSum(demo, demo.length)); } } Consider the recursive function you wrote in the previous problem. Suppose the initial call to the function has an array of N elements, how many recursive calls will be made? How many statements are executed in each call? What is the total number of statements executed for all recursive calls? What is the big O for this function?
Functional meaning for the development of sequential structure is O a. pseudocode Ob. flowchart C. stepping d. selection e. looping
can you please fix the AssertionError in this and also the code: (please don't use try and except or break/continue or recursion) def hike_unique(m: list[list[int]], start_point: tuple[int, int],end_point: tuple[int, int]) -> int: if start_point == end_point:return 0else:front_row = start_point[0]front_column = start_point[1]end_row = end_point[0]end_column = end_point[1]front_eva = m[front_row][front_column]end_eva = m[end_row][end_column]eva_diff = abs(front_eva - end_eva)if front_row == end_row:total_cost = eva_diff * (abs(front_column - end_column)) + 1elif front_column == end_column:total_cost = eva_diff * (abs(front_row - end_row)) + 1else:total_cost = eva_diff * (abs(front_row - end_row) + abs(front_column - end_column)) - 1return total_cost print(hike_unique(sample_map, (1, 1), (0, 0)) It should print 3 if the sample_map is >>> sample_map = [[1, 3], ... [0, 4]] if you do…
public class ArraySection { static void arraySection(int a[], int b[]) { int k = 0; int [] c = new int[a.length]; for(int i = 0; i < a.length; i++) { for(int j = 0; j < b.length; j++) if(a[i] == b[j]) c[k++] = a[i]; } for(int i = 0; i < k; i++) System.out.println(c[i]); System.out.println(); } public static void main(String[] args) { int a[] = { 1, 2, 3, 4, 5 }; int b[] = { 0, 2, 4,5 }; arraySection(a,b); }} Calculate the algorithm step number and algorithm time complexity of the above program?
The task is to get input (n) and make a list from 2 to n and remove its multiples from the list by applying recursive functions. Example: Input: 6 Output: [2, 3, 4, 5, 6] How to apply this python code in the task? def createList(n): #Base Case/s #TODO: Add conditions here for your base case/s #if <condition> : #return <value> #Recursive Case/s #TODO: Add conditions here for your recursive case/s #else: #return <operation and recursive call> #remove the line after this once you've completed all the TODO for this function return [] def removeMultiples(x, arr): #Base Case/s #TODO: Add conditions here for your base case/s #if <condition> : #return <value> #Recursive Case/s #TODO: Add conditions here for your recursive case/s #else: #return <operation and recursive call> #remove the line after this once you've completed all the TODO for this function return []
Integers numberOfParts, required Groups, and invalid Groups are read from input. If numberOfParts is 21 or more, then add 3 to requiredGroups. Otherwise, add 6 to invalidGroups. ► Click here for examples 3 public class GroupSurvey { 4 public static void main(String[] args) { Scanner scnr = new Scanner(System.in); int numberOfParts; int requiredGroups; I int invalidGroups; 345679 8 9 10 11 12 13 14 15 16 17 18 19 20 } numberOfParts = scnr.nextInt (); requiredGroups = scnr.nextInt (); invalidGroups = scnr.nextInt (); /* Your code goes here */ if(numberOfParts>21){ requiredGroups= System.out.println(requiredGroups); System.out.println(invalidGroups);
Python’s list method sort includes the keyword argument reverse, whose defaultvalue is False. The programmer can override this value to sort a list in descendingorder. Modify the selectionSort function so that it allowsthe programmer to supply this additional argument to redirect the sort. selectionSort function: def selectionSort(lyst, profiler):i = 0 while i < len(lyst) - 1:minIndex = ij = i + 1 while j < len(lyst):profiler.comparison() # Countif lyst[j] < lyst[minIndex]:minIndex = jj += 1 if minIndex != i:swap(lyst, minIndex, i, profiler)i += 1 def swap(lyst, i, j, profiler):"""Exchanges the elements at positions i and j."""profiler.exchange() # Counttemp = lyst[i]lyst[i] = lyst[j]lyst[j] = temp Use this template in Python to modify the function above: def selection_sort(input_list, reverse):sorted_list = []#TODO: Your work here# Return sorted_listreturn sorted_listif __name__ == "__main__":my_list = [1, 2, 3, 4, 5]print(selection_sort(my_list, True)) # Correct Output: [5,…
Consider the following recursive method: public int recursiveMethod (int n) if (n <= 0) return 0; else int smaller = n - 1; return recursiveMethod (smaller) + n (n - 1); What is the integer return of a call recursiveMethod (5)? 36 39 40 44 Next Page Previous Page
IN JAVA PLEASE, need help finding an element in the list /** * Returns whether the given value exists in the list. * @param value - value to be searched. * @return true if specified value is present in the list, false otherwise. */ public int indexOf(int value) { //Implement this method return -1; }
int sum, k, i, j; int x[4] [4]={1,2,3,4}, {5,6,7,8},{9,8,7,3},{2, 1,7,1}; sum=x[0] [0]; for (k=1; k<=3;k++) sum+=x[k] [k]; Give the value in sum after the statements are executed: