Consider the following reaction where K = 1.80 x 104 at 298 K. NH4HS (8) NH3(g) + H₂S(9) A reaction mixture was found to contain 0.0584 moles of NH4HS(s), 0.00833 moles of NH3(g), and 0.0134 moles of H₂S(g), in a 1.00 liter container. Is the reaction at equilibrium? If not, what direction must it run in order to reach equilibrium? The reaction quotient, Qe, equals The reaction O must run in the forward direction to reach equilibrium. O must run in the reverse direction to reach equilibrium. O is at equilibrium.
Consider the following reaction where K = 1.80 x 104 at 298 K. NH4HS (8) NH3(g) + H₂S(9) A reaction mixture was found to contain 0.0584 moles of NH4HS(s), 0.00833 moles of NH3(g), and 0.0134 moles of H₂S(g), in a 1.00 liter container. Is the reaction at equilibrium? If not, what direction must it run in order to reach equilibrium? The reaction quotient, Qe, equals The reaction O must run in the forward direction to reach equilibrium. O must run in the reverse direction to reach equilibrium. O is at equilibrium.
Chemistry
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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Transcribed Image Text:Consider the following reaction where Ke = 1.80 x 10-4 at 298 K.
NH4HS(s) ⇒ NH3 (9) + H₂S(9)
A reaction mixture was found to contain 0.0584 moles of NH4HS(s), 0.00833 moles of NH3(g), and 0.0134 moles of H₂S(g), in a 1.00 liter container.
Is the reaction at equilibrium?
If not, what direction must it run in order to reach equilibrium?
The reaction quotient, Qe, equals
The reaction
O must run in the forward direction to reach equilibrium.
O must run in the reverse direction to reach equilibrium.
O is at equilibrium.
Expert Solution
Step 1
Given ->
Kc = 1.80 × 10-4
Moles of NH4HS = 0.0584 moles
Moles of NH3 = 0.00833 moles
Moles of H2S = 0.0134 moles
V = 1.00 L
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