Consider the following Newman projection:CH3BrCH3BrBrWhat word or two-word phrase describes this conformation?How many Br atoms are eclipsed by the CH3 group on the front carbon?How many CH3 groups are gauche to the CH3 group on the front carbon?How many Br atoms are anti to the CH3 group on the front carbon?☐☐☐

Approach to solving the question: Detailed explanation:a. The conformation shown by the Newman…

Answered: Consider the following Newman…

Human Anatomy & Physiology (11th Edition)

11th Edition

ISBN:9780134580999

Author:Elaine N. Marieb, Katja N. Hoehn

Publisher:Elaine N. Marieb, Katja N. Hoehn

Chapter1: The Human Body: An Orientation

Section: Chapter Questions

Problem 1RQ: The correct sequence of levels forming the structural hierarchy is A. (a) organ, organ system,...

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DHA is a fatty acid derived from fish oil and an abundant fatty acid invertebrate brains. Hydrogenation of DHA forms docosanoic acid[CH3(CH2)20CO2H], and ozonolysis forms CH3CH2CHO, CH2(CHO)2 (fiveequivalents), and HCOCH2CH2CO2H. What is the structure of DHA if all double bonds have the Z configuration?
2. | Calculate the overall charge (pH 7) on the following three polypeptides and answer the questions below. Assume the following pKa values: N-terminal -NH3®, 7.0; all -COOH groups, 4.0; Arg, 12.5; Cys, 8.4; His, 6.0; Lys, 10.0; Tyr, 10.0. (A) Ser-Tyr-Ser-Met-Glu-His-Phe-Arg-Trp-Gly-Lys-Pro-Val-Gly-Lys-Lys-Arg-Arg-Pro-Val-Lys-Val-Tyr-Pro-Asp-Ala -Gly- Glu-Asp-Gln- Ser-Ala-Glu-Ala-Phe-Pro-Leu-Arg-Glu-Phe (B) Ser-Tyr-Ser-Met-Glu–His-Phe-Arg–Trp–Gly-Ala-Pro-Val-Gly-Glu-Glu-Cys-Asp-Pro-Val-Glu–Val-Tyr-Pro-Asp- Ala-Gly-Glu-Asp-Gln-Ser-Ala-Glu-Ala-Phe-Pro-Leu-Glu-Phe-Cys-Ser-Tyr-Ser-Met-Glu-His-Phe-Asp-Trp-Gly- Asp-Pro-Val-Gly-Pro-Asp-Ala-Gly-Asp-Gln-Pro-Val-Gly-Glu-Glu-Cys-Asp-Pro-Val-Glu-Val-Tyr-Pro-Asp-Ala | (C) Gly-Ser-Val-Arg-Asp-Pro-Val-Lys-Glu–Val-Tyr-Pro-Asp- Lys-Ala-Gly-Arg-Glu-Ser-Arg-Ala (a) Which of the three peptides would elute first from a gel filtration column? (b) Which of the three peptides would migrate the fastest on SDS-PAGE (c) Which of the three peptides could be…
d.Which pairs are enantiomers? Which are diastereomers? e.Determine the absolute configuration of each chiral center in one pair of diastereomer.
1.) What type of nucleic acid does this complex occur? 2.) How many 3',5'-Phosphodiester linkages were formed? from the complex of the given structure? Give ONLY the NUMBER of the linkages. 3.) Name the second complementary base from the 5' direction.
Select the correct match : 1.Reducing sugar — Sucrose 2.Phosphodiester bond — Between nucleotides on antiparallel strands of DNA 3.Glycosidic bond — Between repeating units of starch and in glycogen 4.Peptide bond — Formed by elimination of H2 between amino acids
1. (a) The diagram below shows a structure of monosaccharide. CH,OH C=0 H-C-OH НО—С—Н ČH,OH i. Draw the figure above on your answer sheet and indicate ALL chiral carbon(s) in your figure with *. ii. With reference to the number of carbon, the type of carbonyl group and D/L configuration, suggest a name consisting these three properties to describe the monosaccharide shown above. Explain why this monosaccharide is in D- or L- configuration as you suggested in (ii). 111. (b) The diagram below shows different configurations of glucose. CH,OH CHO ÇH,OH H H-C-OH O. OH H. H. OH H. H OH HO-C-H но H-C-OH но H. H-C-OH OH OH ČH,OH A В C i. Which glucose molecule, A or C, is in a configuration? Explain. ii. What is the name of the conversion among different configurations? iii. Glycosaminoglycans (GAG) consist of modified sugars. Give a name of the typical modification to the sugar. What makes GAG ideal for the fluid in the joints? to
2
Q1. Give the appropriate name of letter d, e, and f.
Which one bracketed region most likely illustrates a phosphodiester bond in Figure 1? The bracketed region marked ‘i’, from phosphate group to phosphate group. The bracketed region marked ‘j’, from methyl group to methyl group. The bracketed region marked ‘k’, from 3’ carbon to 5’ carbon. None of the above and I have explained my reasoning here.
Consider the following cyclic monosaccharide. CH₂OH H H H H OH HO OH Part 1 of 2 OH H Classify the monosaccharide as an aor ẞ isomer. Select the single best answer. ○ẞ isomer a isomer Part: 1/2 Part 2 of 2 Draw the other isomer of the cyclic form using a Haworth projection. Click and drag to start drawing a structure. ם' G
Consider the structure shown below. он 3 5 CH; O CH, O H CH; O 1 H-N-CH,-C-N-CH;-C-N-CH-C-N-CH-C-N-CH-C-ơ 2 H. H H Fill in the blank with an integer (1, 2, 3, 4, 5..) as shown in the diagram or to represent a specified number. A hydrophilic side chain is indicated by the number
2. | Calculate the overall charge (pH 7) on the following three polypeptides and answer the questions below. Assume the following pKa values: N-terminal –NH3®, 7.0; all -COOH groups, 4.0; Arg, 12.5; Cys, 8.4; His, 6.0; Lys, 10.0; Tyr, 10.0. (A) Ser-Tyr-Ser-Met-Glu-His-Phe-Arg-Trp-Gly-Lys–Pro–Val–Gly–Lys–Lys–Arg-Arg-Pro-Val-Lys–Val-Tyr-Pro-Asp-Ala -Gly- Glu-Asp-GIn– Ser-Ala-Glu-Ala-Phe-Pro-Leu-Arg-Glu-Phe (B) Ser-Tyr-Ser-Met-Glu-His-Phe-Arg-Trp-Gly-Ala-Pro-Val-Gly-Glu-Glu–Cys-Asp-Pro-Val-Glu–Val–Tyr-Pro-Asp- Ala-Gly-Glu-Asp-Gln-Ser-Ala-Glu-Ala-Phe-Pro-Leu-Glu-Phe-Cys-Ser-Tyr-Ser-Met-Glu–His-Phe-Asp-Trp-Gly- Asp-Pro-Val-Gly-Pro-Asp-Ala-Gly-Asp-Gln-Pro-Val–Gly–Glu-Glu-Cys-Asp-Pro–Val-Glu–Val–Tyr-Pro-Asp-Ala (C) Gly-Ser-Val-Arg-Asp-Pro-Val-Lys-Glu-Val-Tyr-Pro-Asp- Lys–Ala-Gly-Arg-Glu-Ser-Arg-Ala (d) Which of the three peptides would migrate the closest to the anode in isoelectric focusing? (e) Which of the above peptides would elute last from a gel filtration column? (f) Which of the three…

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