Identify which letter corresponds to the anomeric carbon in the figure. ### Molecular Structure of DisaccharideThis diagram illustrates the molecular structure of a disaccharide, specifically a two-ring sugar molecule. Each ring represents a monosaccharide that has joined together through a glycosidic bond. The labelled points A, B, C, D, E, and F highlight specific atoms or groups within the molecule.1. **Point A (CH2OH)**: This is a hydroxymethyl group attached to the carbon atom in the monosaccharide ring.2. **Point B (-O- glycosidic bond)**: The oxygen bridge connecting the two monosaccharide units. This bond is formed through a dehydration reaction, where a water molecule is removed to join the two monosaccharides.3. **Point C (OH)**: This represents a hydroxyl group attached to a specific carbon atom in the monosaccharide ring.4. **Point D (HO)**: Another hydroxyl group in the second monosaccharide unit.5. **Point E (CH2OH)**: A hydroxymethyl group similar to Point A, attached to the carbon in the second monosaccharide ring.6. **Point F (CH2OH)**: Another hydroxymethyl group in the first monosaccharide ring similar to Point A.### Understanding Glycosidic LinkageThe bond between the two monosaccharides is known as a glycosidic linkage. This bond is a crucial feature in the formation of disaccharides, oligosaccharides, and polysaccharides. It can occur between different carbon atoms of the monosaccharides, leading to various types of glycosidic bonds such as α (alpha) and β (beta) linkages, which can significantly affect the properties and digestibility of the sugars.### Hydroxyl Groups (OH and HO)Hydroxyl groups (-OH and HO-) are essential functional groups in sugars, influencing their solubility and reactivity. Their position and orientation can also affect the overall structure and function of the sugar molecule.This structure is fundamental in biochemistry, where understanding the formation and breakdown of disaccharides is crucial for studying metabolism, energy storage, and cellular processes.

Anomeric carbon is the carbon which bears a hemiacetal or acetal or hemiketal or ketal. In the…

Answered: H CH2OH ОН A CH₂OH B C Но E CH₂OH

Science

Biochemistry

H CH2OH ОН A CH₂OH B C Но E CH₂OH

Biochemistry

9th Edition

ISBN:9781319114671

Author:Lubert Stryer, Jeremy M. Berg, John L. Tymoczko, Gregory J. Gatto Jr.

Publisher:Lubert Stryer, Jeremy M. Berg, John L. Tymoczko, Gregory J. Gatto Jr.

Chapter1: Biochemistry: An Evolving Science

Section: Chapter Questions

Problem 1P

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Aldose monosaccharides can be oxidized when treated with a mild oxidizing agent. In this reaction, the aldehyde group of the open-chain aldose is oxidized to a carboxylic acid group. In basic solution, ketose monosaccharides can also be oxidized, forming carboxylic acids because they can undergo a rearrangement to an aldose form. Monosaccharides (cyclic hemiacetals) can also react with an alcohol to form acetals, called glycosides, and water. In this reaction, the OH of the anomeric carbon is replaced by the OR group of the alcohol. D-ribose (Figure 1) is treated with a mild oxidizing agent. Edit the structure for D-ribose to show the product of this reaction. M Edit the molecule on the canvas by choosing buttons from the Tools (for bonds), Atoms, and Advanced Template toolbars. The single bond is active by default. Include all hydrogen atoms. ► View Available Hint(s) [1] A H 12D H H H H 7 L EXP. CONT.i L 1 -O-H O H ew -O-H enodic Table -O-H H C N O S CI Br I P F