Consider the following competing hypotheses: (You may find it useful to reference the appropriate table: z table or ttable)Hypotheses: He: HD 3 5; HA: HD > 5Sample results: d = 9.5, Sp6.2, n = 13The following results are obtained using matched samples from two normally distributed populations:a. Calculate the value of the test statistic, assuming that the sample difference is normally distributed. (Negative value should beindicated by a minus sign. Round final answer to 3 decimal places.)Test statistic1.836b. Find the p-value.O 0.01 Picture p-value < 0.025O p-value < 0.01O p-value Picture 0.10O 0.05 Picture p-value < 0.10O 0.025 Picture p-value < 0.05c. Use the 5% significance level to make a conclusion.O Do not reject Ho since the p-value is more than a.Reject Ho since the p-value is more than a.O Do not reject Ho since the p-value is less than a.O Reject Ho since the p-value is less than a. d. Interpret the results at a = 0.05.We cannot conclude that that the mean difference is greater than 5.We conclude that the mean difference is greater than 5.We cannot conclude that the mean difference differs from zero.O We conclude that the mean difference differs from zero.

Answered: Image /qna-images/answer/b85c44c0-0289-4843-9def-f4479c9e5871.jpg

Answered: Consider the following competing…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Question 2 Test the claim that the mean GPA of night students is significantly different than 2.7 at the 0.01 significance level. The null and alternative hypothesis would be: Ho:µ = 2.7 Ho:p= 0.675 Ho: H = 2.7 Ho:p= 0.675 Ho:p= 0.675 Ho:u = 2.7 H1:µ 2.7 H1:p 0.675 H1: µ > 2.7 %3D The test is: left-tailed right-tailed two-tailed Based on a sample of 70 people, the sample mean GPA was 2.66 with a standard deviation of 0.03 The test statistic is: (to 2 decimals) The positive critical value is: (to 2 decimals) Based on this we: O Reject the null hypothesis O Fail to reject the null hypothesis
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Below is the question I am having a problem with as well as the portion of the answer I have come up with. I do not know if I am right or not, but I need an explanation to understand this, please. What information does the F ratio on the SPSS output for an independent sample T test provide? That is, what assumption does it test. A researcher might use the independent sample t test when he assumes that there will be equal mean populations between to variances. To calculate the independent sample t test, one would use this formula: t = m1-m2 SEm1-m2
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You wish to test the following claim (Ha) at a significance level of a 0.01. Ho:H1 = 42 Ha:H1 > H2 You believe both populations are normally distributed, but you do not know the standard deviations for either. However, you also have no reason to believe the variances of the two populations are not equal. You obtain a sample of size n1 = 25 with a mean of M1 = 52.5 and a standard deviation of SD, = 9.1 from the first population. You obtain a sample of size n2 = 18 with a mean of M2 = 48.7 and a standard deviation of SD2 = 5.2 from the second population. What is the test statistic for this sample? (Report answer accurate to three decimal places.) test statistic What is the p-value for this sample? For this calculation, use the conservative under-estimate for the degrees of freedom as mentioned in the textbook. (Report answer accurate to four decimal places.) p-value = The p-value is... O less than (or equal to) a O greater than a This test statistic leads to a decision to... O reject the…
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Read the following prompt and complete question 2
You wish to test the following claim (Ha) at a significance level of a = 0.001. H.:µ1 = µ2 Ha:µ1 # µ2 You believe both populations are normally distributed, but you do not know the standard deviations for either. However, you also have no reason to believe the variances of the two populations are not equal (So use the "pool" option). You obtain the following two samples of data. Sample #1 Sample #2 86.4 60.5 63.3 93.5 94.6 61.1 99.2 55.9 85.8 107 88.9 68.8 88.3 61.9 78.8 59.2 103.8 99.7 74.3 72.5 76.5 62 70.5 80.7 80.2 59.2 64.3 107 89.3 113.2 48.5 95.2 72.1 76.1 115.5 75.1 97.6 88.4 96.4 What is the test statistic for this sample? (Report answer accurate to three decimal places.) test statistic = What is the p-value for this sample? For this calculation, use the P-value reported from the "2-sample t- test" from the technology you are using. (Report answer accurate to four decimal places.) p-value = The p-value is... O less than (or equal to) a greater than a This test statistic leads…
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