Please assist in this multiple comparison problem. The following data are from a completely randomized design.Treatment Treatment TreatmentAB324433304336304435264636324840Sample mean304536Sample variance6.004.006.50a. At the a = 0.05 level of significance, can we reject the null hypothesis that the means of the three treatments are equal?Compute the values below (to 1 decimal, if necessary).Sum of Squares, TreatmentSum of Squares, ErrorMean Squares, TreatmentMean Squares, ErrorCalculate the value of the test statistic (to 2 decimals).The p-value is between 0.01 and 0.025What is your conclusion?Conclude that not all treatment means are equal vb. Calculate the value of Fisher's LSD (to 2 decimals). Use Fisher's LSD procedure to test whether there is a significant difference between the means for treatments A and B, treatments A and C, and treatments B and C. Use a = 0.05.Difference Absolute ValueConclusionTA - TBSignificant differenceTA - TCSignificant differenceSignificant differencec. Use Fisher's LSD procedure to develop a 95% confidence interval estimate of the difference between the means of treatments A and B (to 2 decimals). Enter negative values as negative numbers.

The given summary statistics are as follows:

The following data are from a completely randomized design. Treatment Treatment Treatment A. B 32 44 33 30 43 36 30 44 35 26 46 36 32 48 40 Sample mean 30 45 36 Sample variance 6.00 4.00 6.50 . At the a = 0.05 level of significance, can we reject the null hypothesis that the means of the three treatments are equal? Compute the values below (to 1 decimal, if necessary). Sum of Squares, Treatment Sum of Squares, Error Mean Squares, Treatment Mean Squares, Error Calculate the value of the test statistic (to 2 decimals). The p-value is between 0.01 and 0.025 v What is your conclusion? Conclude that not all treatment means are equal v o. Calculate the value of Fisher's LSD (to 2 decimals).

The following data are from a completely randomized design. Treatment Treatment Treatment A. B 32 44 33 30 43 36 30 44 35 26 46 36 32 48 40 Sample mean 30 45 36 Sample variance 6.00 4.00 6.50 . At the a = 0.05 level of significance, can we reject the null hypothesis that the means of the three treatments are equal? Compute the values below (to 1 decimal, if necessary). Sum of Squares, Treatment Sum of Squares, Error Mean Squares, Treatment Mean Squares, Error Calculate the value of the test statistic (to 2 decimals). The p-value is between 0.01 and 0.025 v What is your conclusion? Conclude that not all treatment means are equal v o. Calculate the value of Fisher's LSD (to 2 decimals).

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Please assist in this multiple comparison problem.

The following data are from a completely randomized design.
Treatment Treatment Treatment
A
B
32
44
33
30
43
36
30
44
35
26
46
36
32
48
40
Sample mean
30
45
36
Sample variance
6.00
4.00
6.50
a. At the a = 0.05 level of significance, can we reject the null hypothesis that the means of the three treatments are equal?
Compute the values below (to 1 decimal, if necessary).
Sum of Squares, Treatment
Sum of Squares, Error
Mean Squares, Treatment
Mean Squares, Error
Calculate the value of the test statistic (to 2 decimals).
The p-value is between 0.01 and 0.025
What is your conclusion?
Conclude that not all treatment means are equal v
b. Calculate the value of Fisher's LSD (to 2 decimals).

Use Fisher's LSD procedure to test whether there is a significant difference between the means for treatments A and B, treatments A and C, and treatments B and C. Use a = 0.05.
Difference Absolute Value
Conclusion
TA - TB
Significant difference
TA - TC
Significant difference
Significant difference
c. Use Fisher's LSD procedure to develop a 95% confidence interval estimate of the difference between the means of treatments A and B (to 2 decimals). Enter negative values as negative numbers.

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