Consider the combination of resistors shown in the figure below.An open circuit containing five resistors starts at point a and ends at point b. The circuit extends to the right from point a and splits into two parallel horizontal branches. There is a 12.0 Ω resistor on the top branch and a 6.00 Ω resistor on the bottom branch. The branches then recombine and the circuit extends to the right to a 5.00 Ω resistor. To the right of the 5.00 Ω resistor, the circuit again splits into two parallel horizontal branches. There is a 4.00 Ω resistor on the top branch and an 8.00 Ω resistor on the bottom branch. The branches then recombine and the circuit extends to the right until it reaches point b.(a) Find the equivalent resistance between point a and b. Ω(b) If a voltage of 65.8 V is applied between points a and b, find the current in each resistor.12 Ω Your response differs from the correct answer by more than 10%. Double check your calculations. A6 Ω A5 Ω A4 Ω A8 Ω A ### Electrical Circuit with Resistors**Diagram Description:**The circuit consists of resistors arranged between points a and b:1. Two parallel branches: - The first branch has two resistors in series: 12.0 Ω and 6.0 Ω. - The second branch has two resistors in series: 4.0 Ω and 8.0 Ω.2. These two branches are connected in parallel with a 5.0 Ω resistor.**Problem Statement:**(a) Calculate the equivalent resistance between points a and b.- **Solution:** The equivalent resistance is given as 11.7 Ω.(b) Given that a voltage of 65.8 V is applied between points a and b, compute the current in each resistor.- **12 Ω Resistor:** A faulty calculation shows 0.63 A with an error message indicating the answer is inaccurate by more than 10%.For the other resistors (6 Ω, 5 Ω, 4 Ω, 8 Ω), the current values need to be determined correctly, as their fields are blank.**Key Learning Points:**- Understanding parallel and series resistor calculations.- Application of Ohm’s Law in calculating current through individual resistors with a known voltage.

Given data: The resistances are, R1=12 ΩR2=6 ΩR3=5 ΩR4=4 ΩR5=8 Ω

Answered: Consider the combination of resistors…

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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Consider the combination of resistors shown in the figure below.

An open circuit containing five resistors starts at point a and ends at point b. The circuit extends to the right from point a and splits into two parallel horizontal branches. There is a 12.0 Ω resistor on the top branch and a 6.00 Ω resistor on the bottom branch. The branches then recombine and the circuit extends to the right to a 5.00 Ω resistor. To the right of the 5.00 Ω resistor, the circuit again splits into two parallel horizontal branches. There is a 4.00 Ω resistor on the top branch and an 8.00 Ω resistor on the bottom branch. The branches then recombine and the circuit extends to the right until it reaches point b.

(a) Find the equivalent resistance between point a and b.
Ω

(b) If a voltage of 65.8 V is applied between points a and b, find the current in each resistor.