Consider Figure 2.12, for which there is an institutional network connected to the Internet. Suppose that the average object size is 1,000,000 bits and that the average request rate from the institution’s browsers to the origin servers is 16 requests per second. Also suppose that the amount of time it takes from when the router on the Internet side of the access link forwards an HTTP request until it receives the response is three seconds on average (see Section 2.2.5). Model the total average response time as the sum of the average access delay (that is, the delay from Internet router to institution router) and the average Internet delay. For the average access delay, use ∆/(1 - ∆b), where ∆ is the average time required to send an object over the access link and b is the arrival rate of objects to the access link. Find the total average response time. I get ∆=1000000/15000000= 1/15, then ∆/(1 - ∆b)= (1/15)/(1-(1/15)*16)=-1, so the finally answer is : 3+(-1)=2s or 3+0=3s?

Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
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Consider Figure 2.12, for which there is an institutional network connected to the Internet. Suppose that the average object size is 1,000,000 bits and that the average request rate from the institution’s browsers to the origin servers is 16 requests per second. Also suppose that the amount of time it takes from when the router on the Internet side of the access link forwards an HTTP request until it receives the response is three seconds on average (see Section 2.2.5). Model the total average response time as the sum of the average access delay (that is, the delay from Internet router to institution router) and the average Internet delay. For the average access delay, use ∆/(1 - ∆b), where ∆ is the average time required to send an object over the access link and b is the arrival rate of objects to the access link.

  1. Find the total average response time.

I get ∆=1000000/15000000= 1/15, then

∆/(1 - ∆b)= (1/15)/(1-(1/15)*16)=-1, so the finally answer is :

3+(-1)=2s or 3+0=3s?

**Figure 2.12: Bottleneck between an institutional network and the Internet**

This diagram illustrates a network configuration, highlighting a bottleneck issue between an institutional network and the Internet. 

- **Origin Servers**: The diagram starts with multiple origin servers which connect to the Internet.

- **Public Internet**: These servers are linked to a public Internet cloud, suggesting data traversing the Internet.

- **15 Mbps Access Link**: The public Internet connects to an access link, which has a bandwidth capacity of 15 Mbps.

- **100 Mbps LAN**: This access link connects further to a Local Area Network (LAN) within an institution, having a higher bandwidth capacity of 100 Mbps.

- **Institutional Network**: The institutional network consists of several computers connected via the 100 Mbps LAN within the organization.

The diagram effectively highlights the bottleneck, which occurs at the 15 Mbps access link between the 100 Mbps LAN of the institution and the broader Internet, potentially causing slower data transfer rates to/from the Internet despite the faster internal network.
Transcribed Image Text:**Figure 2.12: Bottleneck between an institutional network and the Internet** This diagram illustrates a network configuration, highlighting a bottleneck issue between an institutional network and the Internet. - **Origin Servers**: The diagram starts with multiple origin servers which connect to the Internet. - **Public Internet**: These servers are linked to a public Internet cloud, suggesting data traversing the Internet. - **15 Mbps Access Link**: The public Internet connects to an access link, which has a bandwidth capacity of 15 Mbps. - **100 Mbps LAN**: This access link connects further to a Local Area Network (LAN) within an institution, having a higher bandwidth capacity of 100 Mbps. - **Institutional Network**: The institutional network consists of several computers connected via the 100 Mbps LAN within the organization. The diagram effectively highlights the bottleneck, which occurs at the 15 Mbps access link between the 100 Mbps LAN of the institution and the broader Internet, potentially causing slower data transfer rates to/from the Internet despite the faster internal network.
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