Over a network using WEP, we were able to capture two frames with the same Initialization Vector (IV). The following are the encrypted messages: • First frame encrypted message: 1 0 0 1 0 0 1 0 1 0 1 1 0 0 0 0 0 1 1 1 0 1 0 1 1 0 0 1 0 1 1 1 1 0 1 1 0 1 1 0 1 0 0 1 1 1 1 1 1 0 0 1 0 0 0 1 0 0 1 1 1 0 0 0 • Second frame encrypted message: 1 1 0 0 0 0 0 1 1 1 1 0 0 0 0 1 0 0 1 1 0 1 1 1 1 1 0 0 1 0 1 1 1 1 1 0 0 0 1 1 1 1 0 1 1 0 1 0 1 1 0 0 1 1 0 0 0 1 1 0 1 1 1 0 We also know that one of the messages is a control message with the following plain text content: 0 0 1 1 0 0 0 0 0 0 1 1 0 0 0 0 0 0 1 1 0 0 0 0 0 0 1 1 0 0 0 0 0 0 1 1 0 0 0 0 0 0 1 1 0 0 0 1 0 0 1 1 0 0 1 0 0 0 1 1 1 0 0 0 1. Find the plaintext of the other message. 2. If the captured messages were from two different stations on a network that uses TKIP, is it possible to find the plaintext of the other message? Explain why or why not possible.
Over a network using WEP, we were able to capture two frames with the same
Initialization
• First frame encrypted message:
1 0 0 1 0 0 1 0 1 0 1 1 0 0 0 0 0 1 1 1 0 1 0 1 1 0 0 1 0 1 1 1 1 0 1 1 0 1 1 0 1 0 0 1
1 1 1 1 1 0 0 1 0 0 0 1 0 0 1 1 1 0 0 0
• Second frame encrypted message:
1 1 0 0 0 0 0 1 1 1 1 0 0 0 0 1 0 0 1 1 0 1 1 1 1 1 0 0 1 0 1 1 1 1 1 0 0 0 1 1 1 1 0 1
1 0 1 0 1 1 0 0 1 1 0 0 0 1 1 0 1 1 1 0
We also know that one of the messages is a control message with the following plain
text content:
0 0 1 1 0 0 0 0 0 0 1 1 0 0 0 0 0 0 1 1 0 0 0 0 0 0 1 1 0 0 0 0 0 0 1 1 0 0 0 0 0 0 1 1 0 0 0
1 0 0 1 1 0 0 1 0 0 0 1 1 1 0 0 0
1. Find the plaintext of the other message.
2. If the captured messages were from two different stations on a network that uses
TKIP, is it possible to find the plaintext of the other message? Explain why or
why not possible.
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