Consider dilutions: M1V1 = M2V2, lets say M1 = 12.0 M and V2 = 1.OLand M2 = 2.0 M, would V2 be higher, lower or same (unchanged) O V2 must decrease in order to account for M2 being lower O V2 does not change O V2 must increase in order to account for M2 being lower

Consider dilutions: M1V1 = M2V2, lets say M1 = 12.0 M and V2 = 1.OLand M2 = 2.0 M, would V2 be higher, lower or same (unchanged) O V2 must decrease in order to account for M2 being lower O V2 does not change O V2 must increase in order to account for M2 being lower

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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6. Gas containers A and B each contains an ideal gas at low pressure and 298 K. The volume of container A is twice that of container B, but the number of moles of ideal gas contained in A is only halfof that in B. a. Calculate the ratio of the gas pressures in the two containers. b. If the ideal gas in container A is replaced by an equal number of moles of carbon diaxide, which cannot be conside redas an ideal gas under these conditions, how will the pressure in container A change? Explain.
For many purposes we can treat butane (C,H10) as an ideal gas at temperatures above its boiling point of – 1. °C. 3 Suppose the pressure on a 8.0 m° sample of butane gas at 11.0°C is reduced to one-third its initial value. O yes Is it possible to change the temperature of the butane at the same time such that the volume of the gas doesn't change? olo O no If you answered yes, calculate the new temperature of the gas. Round your answer to the nearest °C. Explanation Check © 2021 McGraw Hill LLC. All Rights Reserved. Terms of Use | Privacy Center Accessibility
Given the following equations H/M=K LIN=KP Combine the two equations and solve for P
In Dalton's Law of Partial Pressures: Ptrapped gas = Pdry gas + Pwater vapor Why must the pressure of water vapor be included in this calculation? a. The pressure exerted by the evolved H2(g) is reduced because of the co-presence of water vapor, thus Pwater vapor has to be added to Pdry gas. b. Some of the liquid water evaporates into the gas, and increases the total pressure generated by the trapped gas. c. As the H2(g) is bubbled up the reaction solution, some of the H2(g) molecules are solubilized by water in the aqueous solution, effectively decreasing the measured pressure above. d. The pressure contributed by the H2(g) is greater than the measured total pressure because of the contribution of partial pressure of water vapor.
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Ar 18 Q9 Calculate the pressure in a 212 Liter tank containing 23300 g of Argon gas at 25°C?