10. Hydrogen peroxide, H.O., will spontaneously disproportionate into molecular oxygen and water according to the following reaction: 2H.O. - 2H.O. + 0. 5.00 ml. sample of 3.0% aqueous hydrogen peroxide is placed in a test tube and reacted according to the above reaction; the oxygen gas is collected over water at 28 °C. a) Assuming the density of the hydrogen peroxide solution is 1.00 g/ml, what is the mass of hydrogen peroxide in the sample? b) Given the vapor pressure of water at 28 °C is 28.3 torr, what is the volume of oxygen gas isolated from the above reaction if the total pressure is 755.2 torr?

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10. Hydrogen peroxide, H.O2, will spontaneously disproportionate into molecular oxygen and water
according to the following reaction:
2H.O. - 2H,O. + 0.
5.00 mL sample of 3.0% aqueous hydrogen peroxide is placed in a test tube and reacted according
to the above reaction; the oxygen gas is collected over water at 28 °C.
a) Assuming the density of the hydrogen peroxide solution is 1.00 g/mlL., what is the mass of
hydrogen peroxide in the sample?
b) Given the vapor pressure of water at 28 °C is 28.3 torr, what is the volume of oxygen gas
isolated from the above reaction if the total pressure is 755.2 torr?
Transcribed Image Text:10. Hydrogen peroxide, H.O2, will spontaneously disproportionate into molecular oxygen and water according to the following reaction: 2H.O. - 2H,O. + 0. 5.00 mL sample of 3.0% aqueous hydrogen peroxide is placed in a test tube and reacted according to the above reaction; the oxygen gas is collected over water at 28 °C. a) Assuming the density of the hydrogen peroxide solution is 1.00 g/mlL., what is the mass of hydrogen peroxide in the sample? b) Given the vapor pressure of water at 28 °C is 28.3 torr, what is the volume of oxygen gas isolated from the above reaction if the total pressure is 755.2 torr?
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