Consider a system with Lagrangian L(q.4) = km²q* + amậ²V (q) + BV(q)² %3D where a and B are constants to be determined. Does L give identical physics to the usual Lagrangian L= }mq² – V (q) for a particle in a potential, for any potential V(q)? Why?
Consider a system with Lagrangian L(q.4) = km²q* + amậ²V (q) + BV(q)² %3D where a and B are constants to be determined. Does L give identical physics to the usual Lagrangian L= }mq² – V (q) for a particle in a potential, for any potential V(q)? Why?
Related questions
Question

Transcribed Image Text:Consider a system with Lagrangian
L(q,4) = m²q* + amv (q) + BV(q)²
where a and ß are constants to be determined.
Does L give identical physics to the usual Lagrangian L= mq? – V(q) for a particle
in a potential, for any potential V (q)? Why?
Expert Solution

This question has been solved!
Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.
Step by step
Solved in 2 steps with 2 images
