Consider a standardized two-sided CUSUM with k = 0.2 and h = 8. (a) Use Siegmund's procedure to evaluate the in-control ARL performance of this scheme. (b) Find the out-of-control ARL for 8 = 0.5
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- A diet center wanted to test three different methods for losing weight to determine if the average weight loss (reported in pounds/week) for each method is the same. The results for the three methods are tabulated below. Given that there is a significant difference between the three methods, use the Tukey test to determine if there is a significant difference between each pair of methods. Let a=0.05. (picture attached)Is sunscreen with an SPF 30 rating more effective at preventing sunburn than sunscreen with an SPF 15 rating? At the a = 0.01 level of significance, test the claim that SPF 30 sunscreen is better at preventing sunburn than SPF 15 sunscreen. Let pi5 represent the proportion of SPF 15 sunscreen wearers who get a sunburn and p30 represent the proportion of SPF 30 sunscreen wearers who get a sunburn.(Round your results to three decimal places) Which would be correct hypotheses for this test? O Ho:P15 p30 O Ho: P15 = P30, H1: P15 > P30 O Ho:P15 = p30, H1: P15 7 P30 O Ho:P15 = P30, H1:P15 < P30 A random sample of 100 beach-goers were given SPF 15 sunscreen and asked to lay in the sun for 1 hour. 16 of them later reported a sunburn. Another random sample of 100 beach-goers were given SPF 30 sunscreen and asked to lay in the sun for 1 hour. 13 of them later reported a sunburn. Find the test statistic: Give the P-value: Which is the correct result: O Do not Reject the Null Hypothesis O Reject…how do you find the p-vale in a chi square test?
- Each participant in the study was assigned to a group (Group 1, Group 2, and Group 3). Since the ANOVA was significant, pairwise comparisons were conducted. The researcher found, F( ? ,108) = 6.60, p < .025. What is the df for the numerator?A television manufacturer claims that (at least) 90% of its TV sets will not need service during the first 3 years of operation. A consumer agency wishes to check this claim, so it obtains a random sample 100 purchasers and asks each whether the set purchased needed repair during the first 3 years after purchase. Let p be the sample proportion of responses indicating no repair (so that no repair of n = is identified with a success). Let p denote the actual proportion of successes for all sets made by this manufacturer. The agency does not want to claim false advertising unless sample evidence strongly suggests that p < 0.9. The appropriate hypotheses are then Ho: p = 0.9 versus H: p < 0.9. %3DSuppose P(A) = P(B) = 0.25 and P(AUB) = 0.45. What is P(AN B)?
- A study was conducted of people who had bicycle crashes and whether or not they suffered facial injuries. Based on a sample of 531 individuals these results wer No Helmet Worn Facial Injuries No Facial Injuries Helmet Worn x² = 30 83 182 236 The correct approach is a Chi-square test for categorical data. Calculate the Chi-square statistic and enter it below. (0 - E)²For this problem, carry at least four digits after the decimal in your calculations. Answers may vary slightly due to rounding. Santa Fe black-on-white is a type of pottery commonly found at archaeological excavations at a certain monument. At one excavation site a sample of 582 potsherds was found, of which 356 were identified as Santa Fe black-on-white. LUSE SALT (a) Let p represent the proportion of Santa Fe black-on-white potsherds at the excavation site. Find a point estimate for p. (Round your answer to four decimal places.) (b) Find a 95% confidence interval for p. (Round your answers to three decimal places.) lower limit upper limit Give a brief statement of the meaning of the confidence interval. O 5% of all confidence intervals would include the true proportion of potsherds. O 5% of the confidence intervals created using this method would include the true proportion of potsherds. O 95% of all confidence intervals would include the true proportion of potsherds. O 95% of the…What does the chi-square test of independence test for? a.if the two variables tested combine somehow to influence the frequencies observed b.if the two variables are significantly similar to each other c.if the two variables tested are both dependent on the frequencies c.if the two variables are significantly different from each other
- A manufacturer wants to increase the shelf life of a line of cake mixes. Past records indicate that the average shelf life of the mix is 231 days. After a revised mix has been developed, a sample of nine boxes of cake mix gave these shelf lives (in days): 230,233, 235, 236, 233, 240, 240, 241, and 237. Using α = 0.025, has the shelf life of the cake mix increased? Multiple Choice Yes, because computed t is greater than the critical value. Yes, because computed t is less than the critical value. No, because computed t lies in the region of acceptance. No, because 236.11 is quite close to 231.What percentage of scores is between a z of ‐2 and a z of +2? Why is this important?For F(2,54) = 6.10, p <.01 was the result statistically signifigant
