Q1: Let = (0, 1) and Q = [0, 1]. Let L(0, a) = (a)2 and let X ~ B(n, 0). Let the prioir distrin is Ꮎ ~ Beta(a, b) = г (a + B) pa−1 (1 - 0) ³-1, 0 € (0, 1), a > 0, ẞ > 0. г(a)г(B) 1. Show that the Bayes rule is α + x d(x) = = a + B + n 2. Show that the maximum likelihood estimate of 0 d₁(x) = x/n, is not a Bayes rule. 3. Show that d₁(x) is a limit of Bayes rules. π(0) = 1/(0(1 − 0)). 4. Show that d₁(x) is generalized Bayes with respect to 0 = π 5. Show that d₁(x) is extended Bayes.
Q1: Let = (0, 1) and Q = [0, 1]. Let L(0, a) = (a)2 and let X ~ B(n, 0). Let the prioir distrin is Ꮎ ~ Beta(a, b) = г (a + B) pa−1 (1 - 0) ³-1, 0 € (0, 1), a > 0, ẞ > 0. г(a)г(B) 1. Show that the Bayes rule is α + x d(x) = = a + B + n 2. Show that the maximum likelihood estimate of 0 d₁(x) = x/n, is not a Bayes rule. 3. Show that d₁(x) is a limit of Bayes rules. π(0) = 1/(0(1 − 0)). 4. Show that d₁(x) is generalized Bayes with respect to 0 = π 5. Show that d₁(x) is extended Bayes.
Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter6: The Trigonometric Functions
Section6.6: Additional Trigonometric Graphs
Problem 78E
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MATHEMATICAL STATISTICS A DECISION THEORETIC APPROACH
![Q1: Let
=
(0, 1) and Q
=
[0, 1]. Let L(0, a)
=
(a)2 and let X ~ B(n, 0). Let the
prioir distrin is
Ꮎ
~
Beta(a, b)
=
г (a + B) pa−1 (1 - 0) ³-1, 0 € (0, 1), a > 0, ẞ > 0.
г(a)г(B)
1. Show that the Bayes rule is
α + x
d(x) =
=
a + B + n
2. Show that the maximum likelihood estimate of 0 d₁(x) = x/n, is not a Bayes
rule.
3. Show that d₁(x) is a limit of Bayes rules.
π(0) = 1/(0(1 − 0)).
4. Show that d₁(x) is generalized Bayes with respect to 0 = π
5. Show that d₁(x) is extended Bayes.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F49b7f2d4-d87f-44ed-ad28-2fe8aa7f8d3c%2Fce5bac62-86cb-4596-bdea-25d8438402db%2Fpw85hk_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Q1: Let
=
(0, 1) and Q
=
[0, 1]. Let L(0, a)
=
(a)2 and let X ~ B(n, 0). Let the
prioir distrin is
Ꮎ
~
Beta(a, b)
=
г (a + B) pa−1 (1 - 0) ³-1, 0 € (0, 1), a > 0, ẞ > 0.
г(a)г(B)
1. Show that the Bayes rule is
α + x
d(x) =
=
a + B + n
2. Show that the maximum likelihood estimate of 0 d₁(x) = x/n, is not a Bayes
rule.
3. Show that d₁(x) is a limit of Bayes rules.
π(0) = 1/(0(1 − 0)).
4. Show that d₁(x) is generalized Bayes with respect to 0 = π
5. Show that d₁(x) is extended Bayes.
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