7.2 Two cholesterol-lowering medications (statins) and a placebo were given to each of 10volunteers with total cholesterol readings of 240 or higher. After 6 weeks, the followingtotal cholesterol values were recorded:Statin A: 220 190 180 185 210 170 178 200 177 189Statin B: 160 168 178 200 172 155 159 167 185 199Placebo: 240 220 246 244 198 238 277 255 190 188=2 Chapter 7Analysis of VarianceCreate a SAS data set by reading these data. As an interesting exercise, try readingthree lines like this:220 190 180 185 210 170 178 200 177 189160 168 178 200 172 155 159 167 185 199240 220 246 244 198 238 277 255 190 188That is, have the program create the treatment variable (call it TREAT) with values of'A', 'B', and 'Placebo'. Next run a oneway ANOVA followed by a Student-Newman-Keulsmultiple-comparison test.stand before (Use SAS) Do problem 7.2 on p.232 in Applied Statistics and the SAS ProgrammingLanguage. (Hint: For 7.2, use two DO loops, you may want to look at p.215 for anexample SAS code)Here is the data for problem 7.2:220 190 180 185 210 170 178 200 177 189160 168 178 200 172 155 159 167 185 199240 220 246 244 198 238 277 255 190 188

Answered: 7.2 Two cholesterol-lowering…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Statistics students in Oxnard College sampled 11 textbooks in the Condor bookstore and recorded the number of pages in each textbook and its cost. The bivariate data are shown below: Number of Pages (xx) Cost(yy) 957 148.98 624 100.36 869 137.66 281 40.34 259 39.26 579 82.06 309 52.26 485 83.9 797 113.58 338 54.32 911 138.54 A student calculates a linear modelyy = xx + . (Please show your answers to two decimal places)Use the model to estimate the cost when number of pages is 200.Cost = $ (Please show your answer to 2 decimal places.)
Given the data below, what is the calculated test statistic? Placebo Medication 1 Medication 2 3 4 9 1 3 7 3 5 8 2 5 11 4 4 9 3 SS1 = 5.33 SS2 = 2.8 SS3 = 8.8 T1 = 16 T2 = 21 T3 = 44 n1 = 6 n2 = 5 n3 = 5 ∑X2 = 53 Do you reject the null? Yes No Was there a treatment effect for type of medication on number of anti-anxiety symptoms? Yes No
The manager knows from previous years that the company will provide an annual bonus if theaverage sales per customer is greater than $80.00. Based on this sample – with a 5% level ofconfidence – should they expect an annual bonus? t-Test: Paired Two Sample for Means Variable 1 Variable 2 Mean 77.6005 0 Variance 3098.585 0 Observations 100 100 Pearson Correlation #DIV/0! Hypothesized Mean Difference 80 df 99 t Stat -0.43106 P(T<=t) one-tail 0.33368 t Critical one-tail 1.660391 P(T<=t) two-tail 0.667361 t Critical two-tail 1.984217 Here is the data that I ran through excel. I am having a hard time with the hypothesis, decision, and summary.
The accompanying data table contains chest deceleration measurements (in g, whereg is the force of gravity) from samples of small, midsize, and large cars. Shown are the technology results for analysis of variance of this data table. Assume that a researcher plans to use a 0.05 significance level to test the claim that the different size categories have the same mean chest deceleration in the standard crash test. Complete parts (a) and (b) below. Click the icon to view the table of chest deceleration measurements A Click the icon to view the table of analysis of variance results. ..... a. What characteristic of the data specifically indicates that one-way analysis of variance should be used? O A. There are three samples of measurements. O B. The population means are approximately normal. O C. The measurements are categorized according to the one characteristic of size. O D. Nothing specifically indicates that one-way analysis of variance should be used. b. If the objective is to test…
A new study has found that, on average, 6- to 12-year-old children are spending less time on household chores today compared to 1981 levels. Suppose two samples representative of the study's results report the following summary statistics for the two periods. 1981 Levels 2008 Levels 24 minutes 19 minutes 51 = 3.5 minutes 52 - 4.3 minutes ni = 30 n2 - 30 Which of the following is the correct value of the test statistic assuming that the unknown population variances are equal? Multiple Cholce Z = -4.94 tss = 4.94 Z = 4.94 t59 = -4.94
"A large candy manufacturer produces, packages and sells packs of candy targeted to weigh 52 grams. A quality control manager working for the company was concerned that the variation in the actual weights of the targeted 52-gram packs was larger than acceptable. That is, he was concerned that some packs weighed significantly less than 52-grams and some weighed significantly more than 52 grams. In an attempt to estimate the variance of the weights of all of the 52-gram packs the manufacturer makes, he took a random sample of n = 20 packs off of the factory line. The random sample yielded a sample variance of 3.5 grams. Use 90% confidence level. What is the confidence interval for the variance of the weight of the candy?"
An engineer designed a valve that will regulate water pressure on an automobile engine. The engineer designed the valve such that it would produce a mean pressure of 5.5 pounds/square inch. It is believed that the valve performs above the specifications. The valve was tested on 24 engines and the mean pressure was 5.7 pounds/square inch with a variance of 0.49. A level of significance of 0.01 will be used. Assume the population distribution is approximately normal. Make the decision to reject or fail to reject the null hypothesis.
Define ADL or GLS: Bias versus variance?
The grams of carbohydrates for cereals made by three popular cereal manufacturers (Kellogg, General Mills, and Post) were collected and a one-way ANOVA was performed, as displayed in the table below. Analysis of Variance results: Where: mfr="General Mills" or mfr="Kellogg" or mfr="Post" Responses: carbo Factors: mfr Response statistics by factor mfr="General Mills" or mfr="Kellogg" or mfr="P Carbohydrates 20 mir General Mills 22 14.727273 no Means Std. Dev. Std. Error + 3.3478041 0.71375423 15 Kellogg Post 23 15.130435 4.4650598 0.93102933 9 13.222222 1.9220938 0.64069792 ANOVA table Source DF mi SS MS F-Stat P-value 2 23.786927 11.893464 0.86217854 0.4283 51 703.52789 13.794664 10 Total 153 727.31481 General Mills Kellogg Manufacturer Post Which manufacturer has the highest median grams of carbohydrates? Post O Cannot be determined. O General Mills Kellogg myhip
A researcher was interested in comparing the resting pulse rate of people who exercise regularly and people who do not exercise regularly. Independent random samples of 16 people aged 30-40 who do not exercise regularly (sample 1) and 12 people aged 30-40 who do exercise regularly (sample 2) were selected and the resting pulse rate of each person was measured. The summary statistics are as follows: Pulse Rate data Group 1 (no exercise) Group 2 (exercise) average 72.7 69.7 standard deviation 10.9 8.2 sample size 16 12 Test the claim that the mean resting pulse rate of people who do not exercise regularly is greater than the mean resting pulse rate of people who exercise regularly, use 0.01 as the significance level. Round you answer to 3 decimal places. Group of answer choices p-value=0.207, evidence not support claim p-value=0.267, evidence support claim p-value=0.414, evidence not support claim p-value=0.793, evidence not support claim p-value=0.207, evidence…
In a study performed on comfort food eating during times of stress, it was found that mean rated comfort food consumption level (on a scale from 1-20) for a group of students undertaking their exam period was 14. In comparison, a group of students who were not undertaking exams or examination preparation had a mean rated comfort food consumption level of 10. The pooled estimate of the population variance was 64. What is the estimated effect size (d) of the study? 0.80 0.06 0.50 2.00
Refer to the below table. Using an alpha = 0.05, test the claim that IQ scores are the same for children in three different blood lead level groups: low lead level, medium lead level, and high lead level). One-Way Analysis of Variance Summary Table for IQ Measurements for Children among Three Blood Lead Level Groups: Low Lead Level, Medium Lead Level, and High Lead Level. Source df SS MS F p Between-group (treatment) 2 469.1827 2677.864 2.30 0.104 Within-group (error) 118 203.6918 11745.05 Total 120

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