Suppose P(A) = P(B) = 0.25 and P(AUB) = 0.45. What is P(ANB)?
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A: Given, P A=0.493
Q: 14. Given P(E) = 0.15, P(F) = 0.44, and P(E and F) = 0.01, what is P(E or F)?
A: Given,P(E)=0.15P(F)=0.44P(E and F)=0.01
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Q: Explain how does the null hypothesis test using a t ratio.
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Q: Find the P-value.
A: Given : n=1000 , X=850 , p0=0.9 Assume that α=0.05 Our aim is to find the p-value.
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Q: . Given P(E or F) = 0.66, P(F) = 0.12, and P(E and F) = 0.06, what is P(E)?
A: Given, P(E or F) = 0.66 P(F) = 0.12 P(E and F) = 0.06 P(E)=?
Q: If P(T>2.66)=0.06 and P(T<−2.66)=0.06, obtain P(−2.66≤T≤2.66).
A: Given Information: P(T>2.66)=0.06 P(T<−2.66)=0.06, To obtain P(−2.66≤T≤2.66):…
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A: a) Denote p1, p2 as the true population proportions of men and women, who gamble, respectively.
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- Suppose that 1000 customers are surveyed and 850 are satisfied or very satisfied with a corporation's products and services. Test the hypothesis Ho:p = 0.9 against H₁ :p # 0.9at a = 0.092. Find the P-value. Reject Ho. The P-value is less than 0.05 0.001 0.01 eTextbook and Med 0.05 0.0025 0.025 0.005 Save for Later (choose the least possible). Statistical Tables and Charts Attempts: 1 of 3 used Submit Answer2.6 1 Help pleasewhat is the p value for this problem?
- (5.) As mobile phones continue to proliferate, more and more people will watch video content on their phones. In a study released in 2013, the number of mobile phone video viewers in the UK in year t from 2011 through 2017 (so t = 0 to t = 6) will be P(t) = 13.86t0.535What is the relationship between q and p?Suppose the interval for the difference in the average diastolic blood pressure between patients who were asked questions and patients who sat quietly is: (2,7). Which statement is correct? Patients who are asked questions on average have similar blood pressure as patients who sit quietly during blood pressure measuring. Patients who are asked questions on average have the same blood pressure as patients who sit quietly during blood pressure measuring. Patients who are asked questions on average have higher blood pressure than patients who sit quietly during blood pressure measuring. Patients who are asked questions on average have lower blood pressure than patients who sit quietly during blood pressure measuring.
- A television manufacturer claims that (at least) 90% of its TV sets will not need service during the first 3 years of operation. A consumer agency wishes to check this claim, so it obtains a random sample 100 purchasers and asks each whether the set purchased needed repair during the first 3 years after purchase. Let p be the sample proportion of responses indicating no repair (so that no repair of n = is identified with a success). Let p denote the actual proportion of successes for all sets made by this manufacturer. The agency does not want to claim false advertising unless sample evidence strongly suggests that p < 0.9. The appropriate hypotheses are then Ho: p = 0.9 versus H: p < 0.9. %3DAn education researcher claims that 57% of college students work year-round. In a random sample of 600 college students, 342 say they work year-round. At a = 0.05, is there enough evidence to reject the researcher's claim? Complete parts (a) through (e) below. (a) Identify the claim and state Ho and H3. Identify the claim in this scenario. Select the correct choice below and fill in the answer box to complete your choice. (Type an integer or a decimal. Do not round.) OA. % of college students work year-round. O B. At most % of college students work year-round. O C. The percentage of college students who work year-round is not O D. At least % of college students work year-round. Let p be the population proportion of successes, where a success is a college student who works year-round. State H, and Ha. Select the correct choice below and fill in the answer boxes to complete your choice. (Round to two decimal places as needed.) O A. Ho: p> O B. Ho: ps O C. Ho: p= Ha: ps Hại p> H3:p = O D.…For this problem, carry at least four digits after the decimal in your calculations. Answers may vary slightly due to rounding. In a random sample of 540 judges, it was found that 287 were introverts.
- For the situation described below, state the null and alternative hypotheses to be tested. (Enter != for ≠ as needed.) A seed wash is expected to change the proportion p of seeds that germinate when planted in poorly-draining soil. Suppose that the current germination rate is about 70%.would you favor spending more federal tax money en the arts? of a random sample of n, - 237 women, r, responded yes. Another random sample of n-192 men showed that r64 rempended yes. Does this Information Indicate a dference (ether way) between the population proportion of women and the population proportion of men who favor spending more federal tax dollars on the arts? Use a0.0s. (a) what is the level of ugnihcance? State the null and alternate hypotheses OH P, -Pi H, PPa O Hgi P,-Pai Ha P1> Pa (b) what sampling distribution will you use? What assumptions are you making? O The Student's t. The number of trials is suffidently large standard normal. The number of trals is sufficiently large. O The standard normal. We assume the population distributions are appreximately normal. Student's t. we assume the population distributions are approximately normal. what is the value of the sample test statistic? (Test the dfference p.-p.. Do not use rounded values, Round your fnal answer to two…To test the claim that american quarters are biased towards heads, suppose you flip an american quarter n=1000 times and obtain x=515 heads. You determine the p-value for this result is p=0.1714. what is your conclusion.