Consider a situation where a source is emitting a painfully high frequency sound and you want to reduce the observed frequency of the sound by a proportion p, where 0 < p < 1.ª a. With what speed (as a function of the speed of sound, v) must the source must move away from a stationary observer for the observer to hear the sound with the desired reduced frequency?

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Chapter1: Units, Trigonometry. And Vectors
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My answer is incorrect, please write your explanation(process detail) why the answer is v(p)/(1-p) and write why my answer is wrong.

I attach the image and write my process of explanation.

My solution:

When the source is moving away with a speed of vs.

Using Doppler's effect for this case,

f=fo(v/v+vs)

Then the speed f source will be

vs=(fo/f)-1v

putting the values

vs=(fo/pfo)-1v=1p-1v

Hence, the speed of the source (moving away) is vs=1p-1v.

Professor's solution and answer I attach in the image.

source moving aw ay:
f, = f, ()
f, = (1-P) fs
|-p=
Transcribed Image Text:source moving aw ay: f, = f, () f, = (1-P) fs |-p=
2. Consider a situation where a source is emitting a painfully high frequency sound and you want to reduce the
observed frequency of the sound by a proportion p, where 0 <p<1.«
a. With what speed (as a function of the speed of sound, v) must the source must move away from a stationary
observer for the observer to hear the sound with the desired reduced frequency?-
b) vs =
Transcribed Image Text:2. Consider a situation where a source is emitting a painfully high frequency sound and you want to reduce the observed frequency of the sound by a proportion p, where 0 <p<1.« a. With what speed (as a function of the speed of sound, v) must the source must move away from a stationary observer for the observer to hear the sound with the desired reduced frequency?- b) vs =
Expert Solution
Step 1

Given: 

Frequency emitted by source = f

New expected frequency is p times f where p is between 0 and 1.

Stationary observer vobserver =0

Speed of source = v

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