Judith is overseeing the setting up a dangerous stunt for a movie. The script calls for two trains to travel towards each other at 20 m/s to the right and 20 m/s to the left. The rightwards moving train can slow down with an acceleration of 1 m/s² while the leftwards moving train is limited to a deceleration of 0.5 m/s². The trains will both start to slow down a distance of 800 meters from each other. Without using any equations, Judith predicts that the trains will stop nose to nose 200 meters from the right, and 600 meters from the left. these are numbers you want to compare Is Judith correct about the stopping locations of both trains?
Judith is overseeing the setting up a dangerous stunt for a movie. The script calls for two trains to travel towards each other at 20 m/s to the right and 20 m/s to the left. The rightwards moving train can slow down with an acceleration of 1 m/s² while the leftwards moving train is limited to a deceleration of 0.5 m/s². The trains will both start to slow down a distance of 800 meters from each other. Without using any equations, Judith predicts that the trains will stop nose to nose 200 meters from the right, and 600 meters from the left. these are numbers you want to compare Is Judith correct about the stopping locations of both trains?
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Solve the problem exactly like the example problem attached. The problem you're solving has a black background.
Use equation Vf^2=Vi^2+2ax
Givens (right train)
X= Want
t= ?
Vi=
Vf=
a= -1 m/s
Givens (left train)
X= Want
t= ?
Vi=
Vf=
a= -0.5 m/s
Transcribed Image Text:Givens:
x = want
t = ?
Vf² = Vi + дах
0² = 26²³ + 2(-0.5) X
× / 3 0 0
V₁ = 20m/s
V₁ = 0
a = -03-
= 400 -1-x
=
= 400 - X
+ x
X = 400m
4mm
(vf - v₁)
t
Vf=vi + at
v² = v² + 2ax
a=
1
x = v₁t+ = at²
• (0₁ + 0/1 ) c
t
2
x =
the trains will NOT collide, there
is sufficient distance between
them to both fully stop
x
0² = (-20)²
(20)² + 2(15) X
0 = 400 + x
,५००
-Gob
-400M =X
that negative tells us
the direction
410
Givens:
x = want
t = ?
v₁ =-20m/s
Vf=
a = 0.5m/₁²
Transcribed Image Text:Judith is overseeing the setting up a dangerous stunt for a movie. The script calls for two trains
to travel towards each other at 20 m/s to the right and 20 m/s to the left. The rightwards moving train
can slow down with an acceleration of 1 m/s² while the leftwards moving train is limited to a
deceleration of 0.5 m/s². The trains will both start to slow down a distance of 800 meters from each
other. Without using any equations, Judith predicts that the trains will stop nose to nose 200 meters
from the right, and 600 meters from the left.
these are numbers you want to compare
Is Judith correct about the stopping locations of both trains?
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