Answered: = 0 Using Problem 2.11 and 3.39,… | bartleby

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Could you explain the process of getting these expressions? (1 and 2) I don't really get how we got the result. Please explain in details

= 0
Using Problem 2.11 and 3.39,
(1|H|2) = (yo (x) yo (y) y₁ (z) |2x²yz|yo (x) y⁄₁ (v) ¥o (z))
= 2(x²) (0 [y] 1) (1 |z| 0)
S₂
4
(HR)
ħ
2mw KO [x] 1)²²
= 2 ( 2 ) ²
ħ
2
= 2;

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