Please answer question 1.4 (a) in the image with details on how to do it. Thank you.
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Please answer question 1.4 (a) in the image with details on how to do it. Thank you.
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Solved in 2 steps with 1 images
- In the following three scenarios, an object is located on one side of a converging lens. In each case, you must determine if the lens forms an image of this object. If it does, you also must determine the following. • whether the image is real or virtual • whether the image is upright or inverted • the image's location, q • the image's magnification, M The focal length is f = 53.0 cm for this lens. Set both q and M to zero if no image exists. Note: If q appears to be infinite, the image does not exist (but nevertheless set q to 0 when entering your answers to that particular scenario). (a) The object lies at position 53.0 cm. (Enter the value for q in cm.) 9 = M = cm Select all that apply to part (a). U real U virtual O upright inverted no imageOne positive lens (focal length = f1) and one negative lens (focal length = -f2) are placed at a distance d. – All lenses are thin lenses. Find the overall ABCD matrix of the system Find the value of d when “C” of the overall matrix is zero. ( Hint : Find d in terms of f1 and f2) (This is when the focal length of the overall system is infinity.)Draw an image please.
- A virtual upright image is .25 times the size of the object. a) If the object is 20.0 cm in front of the mirror what is the object distance. b) What is the focal length of the mirror and is it concave, convex, or plane? Show the algebraic form of any equation(s) applied. Report answers to with the correct units and number of significant figures.A concave mirror has a radius of curvature of 68.4 inches. How far (in inches) from the mirror is the focal point?A far-sighted patient has contacts' prescription for +3.00 D, and this prescription gives her a perfect vision. What is her near point?