Consider a point in a structural member that is subjected to plane stress. Normal and shear stresses acting on horizontal and vertical planes at the point are shown. If oy = 22 ksi, determine the angle 0, corresponding to the orientation of the maximum in-plane shear stress. 8 ksi 45 ksi O 30.1° or -56.6° O 20.2° or -79.2° O 22.6° or -53.0° O 27.6° or -62.4° O 16.7° or -85.4°
Consider a point in a structural member that is subjected to plane stress. Normal and shear stresses acting on horizontal and vertical planes at the point are shown. If oy = 22 ksi, determine the angle 0, corresponding to the orientation of the maximum in-plane shear stress. 8 ksi 45 ksi O 30.1° or -56.6° O 20.2° or -79.2° O 22.6° or -53.0° O 27.6° or -62.4° O 16.7° or -85.4°
Principles of Foundation Engineering (MindTap Course List)
8th Edition
ISBN:9781305081550
Author:Braja M. Das
Publisher:Braja M. Das
Chapter6: Vertical Stress Increase In Soil
Section: Chapter Questions
Problem 6.4P: Refer to Figure P6.4. A strip load of q = 900 lb/ft2 is applied over a width B = 36 ft. Determine...
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![Consider a point in a structural member that is subjected to plane stress. Normal and shear stresses acting on horizontal and vertical
planes at the point are shown. If oy = 22 ksi, determine the angle 0, corresponding to the orientation of the maximum in-plane shear
stress.
8 ksi
45 ksi
O 30.1° or -56.6°
O 20.2° or -79.2°
O 22.6° or -53.0°
O 27.6° or -62.4°
O 16.7° or -85.4°](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F6c8979d8-92eb-4f8e-b3c8-2d132b46cf92%2F6d2c4361-9683-4591-b82d-e61a8df47023%2Fi2c2pi9_processed.png&w=3840&q=75)
Transcribed Image Text:Consider a point in a structural member that is subjected to plane stress. Normal and shear stresses acting on horizontal and vertical
planes at the point are shown. If oy = 22 ksi, determine the angle 0, corresponding to the orientation of the maximum in-plane shear
stress.
8 ksi
45 ksi
O 30.1° or -56.6°
O 20.2° or -79.2°
O 22.6° or -53.0°
O 27.6° or -62.4°
O 16.7° or -85.4°
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