Consider a particle with initial velocity that has magnitude 12.0 m/s and is directed 60.0 degrees above the negative x axis.

A projectile Has horizontal range R on level ground and reaches maximum height H. Find an expression for its initial speed.

The 18th hole at Pebble Beach Golf Course is a dogleg to the left of length 496.0 m. The fairway off the tee is taken to be the x-direction. A golfer hits his tee shot a distance of 200.0 m, corresponding to a displacement Ar, 200.0 m î, and hits his second shot 190.1 m with a displacement Ar, 170.0 m î + 85.0 m j. What is the final displacement of the golf ball from the tee (in m)? (Express your %3D %3D answer in vector form.) Ar. total m

A projectile is launched from ground level at an angle θ to the top of a cliff which is 195 m away and 155 m high.  If the projectile lands right on the cliff edge 7.6 s after it is fired, find the initial velocity of the projectile.

The position vector of a particle in 2D is given by r(t) = (bwt + b sin(wt)) â + (b + bcos (wt)) ŷ, where b and w are constants. Find the velocity, v(t), and acceleration, a(t), of the particle. Is the speed of the object constant?

a boy fires an arrow from a height of 1.80 m at an angle of 15° above the horizontal towards a target standing 15.00 m in front of him. He misses the target completely, and the arrow goes flying past the target and hits the ground 21.1 m behind the target.   Determine the initial velocity of the arrow in m/s.

A projectile is launched with an initial velocity of 10.0 m/s @30.0° from ground level. What's the displacement of the object in the x-direction upon returning to the ground?

A stone is catapulted at time t=0, with an initial velocity of magnitude 25.0 m/s and at an angle of 40.0 above the horizontal. What are the magnitudes of the (a) horizontal and (b) vertical components of its displacement from the catapult site at t 1.85 s?

A particle moves in the x-y plane with constant acceleration. At time t = 0 s, the position vector for the particle is d = 5.8 m x + 2.1 m y. The acceleration is given by the vector a = 8.3 m/s2 x + 7.8 m/s2 y. The velocity vector at time t = 0 s is v = 5.3 m/s x - 7.5 m/s y. Find the magnitude of the velocity vector at time t = 7.5 s. What is the angle between the velocity vector and the positive x-axis at time t = 7.5 s? What is the magnitude of the position vector at time t = 7.5 s? What is the angle between the position vector and the positive x-axis at time t = 7.5 s?

A bullet is fired upwards at an angle of 10° clockwise with respect to the horizontal from a point on a hill, and it strikes a target on a horizontal level ground 100m below the hill. The initial velocity of bullet is 100 m/s. The actual velocity with which the bullet will strike the ground is m/s.