The two common phases of carbon are diamond and graphite. At 1 atm and 298 K, graphite is more stable, because its Gibbs function is lower by an amount 2.9 kJ/mol. A. Using the densities (3520 kg/m³ for diamond and 2260 kg/m³ for graphite), find the B. pressure required for diamond to become more stable. If this process occurs naturally under rock with density 3000 kg/m³, what depth of rock is required?
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- At what pressure will the mean free path in room-temperature (20°C) nitrogen be 1.3 m ? Express your answer to two significant figures and include the appropriate units. HẢ ? p = Value UnitsNeeds Complete solution with 100 % accuracy.λ=kT/21/2σp is the equation of mean free path. What is the relation of mean free path to temperature, pressure, and molecular cross section. Sketch a plot of the relationship between mean free path and the molecular cross section. Label your axes.
- Calculate the specific heat capacity at constant volume of water vapor, assuming the nonlinear triatomic molecule has three translational and three rotational degrees of freedom and that vibrational motion does not contribute. The molar mass of water is 18.0 g/mol. Express your answer in J/(kg. K). cv = 24.942 17 ΑΣΦ Submit Previous Answers Request Answer X Incorrect; Try Again; 4 attempts remaining Part B Cv = ? The actual specific heat capacity of water vapor at low pressures is about 2000 J/(kg-K). Calculate the molar heat capacity for actual water vapor. Express your answer in J/(kg. K). ΤΙ ΑΣΦ J/(kg. K) ? J/(kg.K)For any gas, C C. - (+7), (7), Suppose you have one mole of a gas that obeys the equation of state, p(v- b) = represents the volume taken up by the molecules in the system, and 3.5 bars and T = 425 K for your gas sample. Hint: Use the equation of state to evaluate the partial derivatives. =RT, where b is the molar volume. Find the value of A if C-C₁=AR when P = 6A 5 L tank contains Argon gas at 55°C and 4.5 atm. Find the total translational kinetic energy of all the Argon atoms in the tank. 1 atm = 1.013 x 10^5 Pa 1 L = 10^-3 m^3 R= 8.314 J/K-mol Molar mass of Argon= 40 Kb=1.38 x 10 ^-23 J/K
- A process at constant volume pressure takes n mole vibrating diatomic from an initial temperature T to a final temperature 3T. Calculate the change in enthalpy, AH. Select one: O a. O b. ΔΗ AH = 9nRT AU = 5n RT O c. AH 11nRT ΔΗ O d. AH = 7nRT -Mercury is the only metal that exists as a liquid (d=13.56 g/cm3) at room temperature. Find the number of moles in 15 mL of mercury.A gas with an initial temperature of 940 °C undergoes the process shown in the figure. (Figure 1) Figure p (atm) 3 2 1- 0 0 100 200 2 300 V (cm³) Part A What type of process is this? Isochoric. Isobaric. Isothermic. Submit ✓ Correct Part B What is the final temperature in °C? Express your answer using two significant figures. T= 3400 °C Submit V= Previous Answers Part C ✓ Correct Previous Answers How many moles of gas are there? Express your answer to two significant figures and include the appropriate units. Submit HÅ A 29 10-4 mol Previous Answers Request Answer P Pearson ?
- 6. The following data show the relation of vapour pressure of liquid Z as a function of temperature. p/mmHg T/°C 17.54 20 31.82 30 55.32 40 92.51 50 149.38 60 233.70 70 Using linear regression technique, compute the molar enthalpy of vaporization of liquid Z!18.16 A sample of a hypothetical ideal gas has a volume of o.5 m3 at a temperature of 5 °C and a pressure of 250 kPa. a. How many molecules of gas are there in this sample? b. How many moles of gas are there in this sample?Help please