The two common phases of carbon are diamond and graphite. At 1 atm and 298 K, graphite is more stable, because its Gibbs function is lower by an amount 2.9 kJ/mol. A. Using the densities (3520 kg/m³ for diamond and 2260 kg/m³ for graphite), find the B. pressure required for diamond to become more stable. If this process occurs naturally under rock with density 3000 kg/m³, what depth of rock is required?

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The two common phases of carbon are diamond and graphite. At 1 atm and 298 K, graphite is
more stable, because its Gibbs function is lower by an amount 2.9 kJ/mol.
A. Using the densities (3520 kg/m³ for diamond and 2260 kg/m³ for graphite), find the
B.
pressure required for diamond to become more stable.
If this process occurs naturally under rock with density 3000 kg/m³, what depth of rock is
required?
Transcribed Image Text:The two common phases of carbon are diamond and graphite. At 1 atm and 298 K, graphite is more stable, because its Gibbs function is lower by an amount 2.9 kJ/mol. A. Using the densities (3520 kg/m³ for diamond and 2260 kg/m³ for graphite), find the B. pressure required for diamond to become more stable. If this process occurs naturally under rock with density 3000 kg/m³, what depth of rock is required?
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