4- Barium titanate BaTiO3 has a phase with structure as in the attached Figure,which the Ba (Ba; 137 g/mol) atoms are at corners of a cube with a Ti (Ti; 48g/mol) atom at the center and Oxygen (O; 16 g/mol) atoms at the center ofeach face of the cube. The mass density of BaTiO3 p= 6.02 g/cm³. If BaTiO3powder is exposed to X-rays with = 0.154 nm in a Debye-Schererexperiment. (NA= 6.02x10²³ mol-¹).#a- Calculate the number of atoms per unit cell?b- What are the coordinates of the atoms Br-Ti-O?BaOi)ii)iii)Tic- Calculate the lattice constant (a)?d- Calculate the Bragg deflection angle for the first peak of:The planes containing Ba and O only? (answer: 0= 11.09⁰)The planes containing Ba, Ti and O? (answer: 0= 15.797°)The planes containing Ti and O only? (answer: 0= 22.644°)

Answered: Image /qna-images/answer/6b58e0f4-df12-4079-8cab-35c3321aae4d.jpg

4- Barium titanate BaTiO3 has a phase with structure as in the attached Figure, which the Ba (Ba; 137 g/mol) atoms are at corners of a cube with a Ti (Ti; 48 g/mol) atom at the center and Oxygen (O; 16 g/mol) atoms at the center of each face of the cube. The mass density of BaTiO3 p= 6.02 g/cm³. If BaTiO3 powder is exposed to X-rays with = 0.154 nm in a Debye-Scherer experiment. (NA= 6.02x1023 mol-¹). a- Calculate the number of atoms per unit cell? b- What are the coordinates of the atoms Br-Ti-O? c- Calculate the lattice constant (a)? Ba O Ti

4- Barium titanate BaTiO3 has a phase with structure as in the attached Figure, which the Ba (Ba; 137 g/mol) atoms are at corners of a cube with a Ti (Ti; 48 g/mol) atom at the center and Oxygen (O; 16 g/mol) atoms at the center of each face of the cube. The mass density of BaTiO3 p= 6.02 g/cm³. If BaTiO3 powder is exposed to X-rays with = 0.154 nm in a Debye-Scherer experiment. (NA= 6.02x1023 mol-¹). a- Calculate the number of atoms per unit cell? b- What are the coordinates of the atoms Br-Ti-O? c- Calculate the lattice constant (a)? Ba O Ti