MXJWA A 4.2 L volume of neon gas (Ne) is at a pressure of 4.1 atm and a temperature of 460 K. The atomic mass of neon is 20.2_g/mol, and the ideal gas constant is R = 8.314.J/mol K. The mass of the neon gas is closest to 8. D. 0.01717 kg 0.00964 kg 0.01566 kg 0.009214 kg E. 0.01636 kg F. 0.01595 kg ARC 1--1

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### Ideal Gas Law Calculation for Neon Gas

Given:
- Volume of neon gas (Ne): \( 42 \, \text{L} \)
- Pressure: \( 0.41 \, \text{atm} \)
- Temperature: \( 460 \, \text{K} \)
- Atomic mass of neon: \( 20.2 \, \text{g/mol} \)
- Ideal gas constant, \( R \): \( 8.314 \, \text{J/(mol·K)} \)

The mass of the neon gas is closest to:

#### Options:
A. \( 0.001717 \, \text{kg} \)  
B. \( 0.009644 \, \text{kg} \)  
C. \( 0.001636 \, \text{kg} \)  
D. \( 0.001566 \, \text{kg} \)  
E. \( 0.009214 \, \text{kg} \)  
F. \( 0.001595 \, \text{kg} \)

### Steps to Solve:
1. **Convert given values to SI units where necessary:**
   - Pressure: \( 0.41 \, \text{atm} = 0.41 \times 101325 \, \text{Pa} = 41543.25 \, \text{Pa} \)
   - Volume: \( 42 \, \text{L} = 42 \times 10^{-3} \, \text{m}^3 = 0.042 \, \text{m}^3 \)
   
2. **Use the ideal gas law \( PV = nRT \) to find the number of moles \( n \):**
   \[
   n = \frac{PV}{RT} 
   \]
   \[
   n = \frac{ (41543.25 \, \text{Pa}) (0.042 \, \text{m}^3)}{ (8.314 \, \text{J/(mol·K)}) (460 \, \text{K})}
   \]
   \[
   n \approx \frac{1744.812}{3812.44} \approx 0.457 \, \text{mol}
   \]

3. **Convert moles of neon
Transcribed Image Text:### Ideal Gas Law Calculation for Neon Gas Given: - Volume of neon gas (Ne): \( 42 \, \text{L} \) - Pressure: \( 0.41 \, \text{atm} \) - Temperature: \( 460 \, \text{K} \) - Atomic mass of neon: \( 20.2 \, \text{g/mol} \) - Ideal gas constant, \( R \): \( 8.314 \, \text{J/(mol·K)} \) The mass of the neon gas is closest to: #### Options: A. \( 0.001717 \, \text{kg} \) B. \( 0.009644 \, \text{kg} \) C. \( 0.001636 \, \text{kg} \) D. \( 0.001566 \, \text{kg} \) E. \( 0.009214 \, \text{kg} \) F. \( 0.001595 \, \text{kg} \) ### Steps to Solve: 1. **Convert given values to SI units where necessary:** - Pressure: \( 0.41 \, \text{atm} = 0.41 \times 101325 \, \text{Pa} = 41543.25 \, \text{Pa} \) - Volume: \( 42 \, \text{L} = 42 \times 10^{-3} \, \text{m}^3 = 0.042 \, \text{m}^3 \) 2. **Use the ideal gas law \( PV = nRT \) to find the number of moles \( n \):** \[ n = \frac{PV}{RT} \] \[ n = \frac{ (41543.25 \, \text{Pa}) (0.042 \, \text{m}^3)}{ (8.314 \, \text{J/(mol·K)}) (460 \, \text{K})} \] \[ n \approx \frac{1744.812}{3812.44} \approx 0.457 \, \text{mol} \] 3. **Convert moles of neon
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