Consider a closed triangular box resting within a horizontal electric field of magnitude E = 30.0 cm 60.0° 10.0 cm E (a) Calculate the electric flux through the vertical rectangular surface of the box. KN • m²/c (b) Calculate the electric flux through the slanted surface of the box. kN·m²/c (c) Calculate the electric flux through the entire surface of the box. KN • m²/c . 6.62 × 104 N/C as shown in the figure below.
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Q: Consider a closed triangular box resting within a horizontal electric field of magnitude E = 7.10 x…
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- An infinitely long cylinder of radius R = 57 cm carries a uniform charge density ρ = 21 μC/m 3. Calculate the electric field (in N/C) at distance r = 19 cm from the axis of the cylinder.A 40.0-cm-diameter circular loop is rotated in a uniform electric field until the position of maximum electric flux is found. The flux in this position is measured to be 5.20 x 105 Nm²/C. What is the magnitude of the electric field?9. The drawing shows an edge-on view of two planar surfaces that intersect and are mutually perpendicular. Surface (1) has an area of 2.50 m², while surface (2) has an area of 2.70 m2. The electric field in the drawing is uniform and has a magnitude of 220 N/C. Find the magnitude of the electric flux through surface (1) if the angle 0 made between the electric field with surface (2) is 32.0°. Nm2/C Surface 1 19.0of19 0of19 00f19 oof19 0of Surface 2 of19 0of19 o 9 00f19 oof1
- A electric field at 3.8 cm from the centre of a long copper rod of radius 0.7 cm has a magnitude 3.6 N/C and is directed outward from the axis of the rod. Part 1 What is the charge per unit length of the copper rod? = number (rtol=0.03, atol=0) C/m Part 2 What would be the electric flux through a cube of side 8.0 cm situated such that the rod passes through the opposite sides of the cube perpendicularly? number (rtol=0.03, atol=0) Nm?/CConsider a closed triangular box resting within a horizontal electric field of magnitude E = 7.76 x 104 N/C as shown in the figure below. 10.0 cm 30.0 cm 60.0⁰ (a) Calculate the electric flux through the vertical rectangular surface of the box. kNm²/C (b) Calculate the electric flux through the slanted surface of the box. kNm²/C Need Help? (c) Calculate the electric flux through the entire surface of the box. kN - m²/c Read It Watch ItConsider a closed triangular box resting within a horizontal electric field of magnitude E = 7.86 x 104 N/C as shown in the figure below. 10.0 cm 30.0 cm 60.0⁰ E (a) Calculate the electric flux through the vertical rectangular surface of the box. kN - m²/c (b) Calculate the electric flux through the slanted surface of the box. kNm²/C (c) Calculate the electric flux through the entire surface of the box. kN - m²/c
- Consider a closed triangular box resting within a horizontal electric field of magnitude E = 7.80×104 N/C as shown in the following figure. Calculate the electric flux through (a) the vertical rectangular surface (the 10 cm × 30 cm surface), (b) the slanted surface, and (c) the entire surface of the box. 10.0 cm 30.0 cm 60.0°Consider a closed triangular box resting within a horizontal electric field of magnitude E = 7.14 x 104 N/C as shown in the figure below. 30.0 cm 60.0° 10.0 cm (a) Calculate the electric flux through the vertical rectangular surface of the box. | kN - m²/c (b) Calculate the electric flux through the slanted surface of the box. kN - m2/c (c) Calculate the electric flux through the entire surface of the box. | kN - m²/cA flat surface of area 3.40 m? is rotated in a uniform electric field of magnitude E = 5.80 x 105 N/C. (a) Determine the electric flux through this area when the electric field is perpendicular to the surface. | N •m²/c (b) Determine the electric flux through this area when the electric field is parallel to the surface. N- m?/c
- Consider a closed triangular box resting within a horizontal electric field of magnitude E = 8.26 104 N/C as shown in the figure below. (a) Calculate the electric flux through the vertical rectangular surface of the box.A right conical frustrum is placed in a uniform electric field that is parallel to the y axis, as shown. The magnitude of the electric field is 43 N/C. The electric flux measured through the top surface is 2240 N-m?/C, and the electric flux measured through the bottom surface is 4480 N-m²/C. What is the electric flux through the side of the frustrum?