Compute AH °1000 of HCI(g) from enthalpies of formation data and these C °[J/(mol K)] P,m expressions, which hold from 298 K to 1500 K. 27.14 + 0.009274 (T/K) – 1.381 (10°T°/K³) + 7.645 (10°r°/K°) 26.93 + 0.03384 (T/K) – 3.896 (10r°/K*) + 15.47 (10¯°T° /K°) 30.67 – 0.007201 (T/K) – 1.246 (10¯³T*/K*) – 3.898 (10¯°T°/K*) -5 -9 „3 for H, (g), Cl, (g), and HCI(g), in that order. 2
Compute AH °1000 of HCI(g) from enthalpies of formation data and these C °[J/(mol K)] P,m expressions, which hold from 298 K to 1500 K. 27.14 + 0.009274 (T/K) – 1.381 (10°T°/K³) + 7.645 (10°r°/K°) 26.93 + 0.03384 (T/K) – 3.896 (10r°/K*) + 15.47 (10¯°T° /K°) 30.67 – 0.007201 (T/K) – 1.246 (10¯³T*/K*) – 3.898 (10¯°T°/K*) -5 -9 „3 for H, (g), Cl, (g), and HCI(g), in that order. 2
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
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Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![Compute AH °1000 of HCI(g) from enthalpies of formation data and these C, [J/(mol K)]
´P,m
expressions, which hold from 298 K to 1500 K.
27.14 + 0.009274 (T/K) – 1.381 (10°T°/K) + 7.645 (10¯°T°/K°)
26.93 + 0.03384 (T/K) – 3.896 (10¯³T°/K°) + 15.47 (10°r°/K°)
30.67 – 0.007201 (T/K) – 1.246 (10¯°Tʻ/K´) – 3.898 (10¯°T° /K`)
-5
-9
for
(g), Cl, (g), and HCI(g), in that order.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F839d9203-ce29-4531-a86e-1f20af375321%2F8e95fbad-d288-41aa-abd8-755006c9aed3%2Fu5vwn8n_processed.png&w=3840&q=75)
Transcribed Image Text:Compute AH °1000 of HCI(g) from enthalpies of formation data and these C, [J/(mol K)]
´P,m
expressions, which hold from 298 K to 1500 K.
27.14 + 0.009274 (T/K) – 1.381 (10°T°/K) + 7.645 (10¯°T°/K°)
26.93 + 0.03384 (T/K) – 3.896 (10¯³T°/K°) + 15.47 (10°r°/K°)
30.67 – 0.007201 (T/K) – 1.246 (10¯°Tʻ/K´) – 3.898 (10¯°T° /K`)
-5
-9
for
(g), Cl, (g), and HCI(g), in that order.
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