THERMODYNAMIC CALCULATIONS TO3/S02 Formula Molar Mass (g/mol) AG°F (kJ/mol) AH°F (kJ/mol) s° (J/(K mol)) NH3(g) -46.11 17.031 O2(g) 31.999 H20(1) 18.015 N2(g) 14.007 T = 298 K R = 8.314 J/(K mol) Calculate the enthalpy of formation (kJ/mol) of H20(1). The enthalpy of reaction for the equation as written is -1531 kJ. If the answer is negative, enter the sign and then the magnitude. Express your answer to three significant figures. 4NH3(g) + 302(g) - 6H20(1) + 2N2(g) the tolerance is +/-2%

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Chapter1: Chemical Foundations
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THERMODYNAMIC CALCULATIONS TO3/S02
Formula Molar Mass (g/mol) AG°F (kJ/mol) AH°F (kJ/mol) s° (J/(K mol))
NH3(g)
-46.11
17.031
O2(g)
31.999
H20(1)
18.015
N2(g)
14.007
T = 298 K
R = 8.314 J/(K mol)
Calculate the enthalpy of formation (kJ/mol) of H20(1). The enthalpy of reaction for the equation as written is -1531 kJ. If the answer is negative, enter the sign and then the magnitude.
Express your answer to three significant figures.
4NH3(g) + 302(g) - 6H20(1) + 2N2(g)
the tolerance is +/-2%
Transcribed Image Text:THERMODYNAMIC CALCULATIONS TO3/S02 Formula Molar Mass (g/mol) AG°F (kJ/mol) AH°F (kJ/mol) s° (J/(K mol)) NH3(g) -46.11 17.031 O2(g) 31.999 H20(1) 18.015 N2(g) 14.007 T = 298 K R = 8.314 J/(K mol) Calculate the enthalpy of formation (kJ/mol) of H20(1). The enthalpy of reaction for the equation as written is -1531 kJ. If the answer is negative, enter the sign and then the magnitude. Express your answer to three significant figures. 4NH3(g) + 302(g) - 6H20(1) + 2N2(g) the tolerance is +/-2%
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