**Problem 3:**Given the following equations and ΔH° values, determine the heat of reaction (kJ) at 298 K for the reaction:\[ 2 \text{SO}_2(g) + 2 \text{P}(s) + 5 \text{Cl}_2(g) \rightarrow 2 \text{SOCl}_2(l) + 2 \text{POCl}_3(l) \]**Reactions and Standard Enthalpies of Formation (ΔH°):**1. \[\text{SOCl}_2(l) + \text{H}_2\text{O}(l) \rightarrow \text{SO}_2(g) + 2 \text{HCl}(g) \quad \Delta H^{\circ} = +10.3 \text{ kJ} \]2. \[\text{PCl}_3(l) + \frac{1}{2} \text{O}_2(g) \rightarrow \text{POCl}_3(l) \quad \Delta H^{\circ} = -325.7 \text{ kJ} \]3. \[\text{P}(s) + \frac{3}{2} \text{Cl}_2(g) \rightarrow \text{PCl}_3(l) \quad \Delta H = -306.7 \text{ kJ} \]4. \[4 \text{HCl}(g) + \text{O}_2(g) \rightarrow 2 \text{Cl}_2(g) + 2 \text{H}_2\text{O}(l) \quad \Delta H = -202.6 \text{ kJ} \]**Explanation:**The given reaction involves combining sulfur dioxide (SO₂), phosphorus (P), and chlorine gas (Cl₂) to form thionyl chloride (SOCl₂) and phosphorus oxychloride (POCl₃). The problem requires the calculation of the overall heat of reaction (ΔH) using the provided standard enthalpy changes for related chemical equations.By applying Hess’s Law—which states that the total enthalpy change for a reaction is the same regardless of the pathway taken—one can rearrange and combine the given reactions to derive the heat of the desired reaction.

Answered: Image /qna-images/answer/d536de26-8758-4c88-9261-8cb56ef7597f.jpg

3. Given the following equations and AH values, determine the heat of reaction (kJ) at 298 K for the reaction: 2 SO2(g) + 2 P(s) + 5 Cl2(g) →2 SOC12(1) + 2 POC13(1) SOC12(1) + H₂O(1) → SO2(g) + 2 HCl(g) PC13(1) + 1/2 O2(g) → POC13(1) P(s) + 3/2 Cl2(g) →→ PC13(1) 4 HCl(g) + 02(g) →2 Cl2(g) +2 H₂O(1) ΔΗ° = +10.3 kJ ΔΗ° = .325.7 kJ AH-306.7 kJ ΔΗ = -202.6 kJ

3. Given the following equations and AH values, determine the heat of reaction (kJ) at 298 K for the reaction: 2 SO2(g) + 2 P(s) + 5 Cl2(g) →2 SOC12(1) + 2 POC13(1) SOC12(1) + H₂O(1) → SO2(g) + 2 HCl(g) PC13(1) + 1/2 O2(g) → POC13(1) P(s) + 3/2 Cl2(g) →→ PC13(1) 4 HCl(g) + 02(g) →2 Cl2(g) +2 H₂O(1) ΔΗ° = +10.3 kJ ΔΗ° = .325.7 kJ AH-306.7 kJ ΔΗ = -202.6 kJ

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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