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4. i. Using the data at the bottom of the question, calculate the enthalpy of formation of W(CO)6(S). ii. At 298 K, the enthalpies of sublimation of W(CO)6(s) and of W(s) are 75.6 and 849.4 kJ mol¹ respectively. Calculate the mean (W-CO) bond dissociation enthalpy in W(CO)6. The following enthalpies of combustion have been measured at 298 K. W(s) + 1.5 O2(g) → WO3(s) W(CO)6(s) + 4.5 O2(g) → WO3(s) + 6CO2(g) CO(g)+0.5 Oz(g) → CO2(g) C(s) + O2(g) → CO2(g) AcH₁ =-842.9 kJ mol¯¹ AcH2 -2242.7 kJ mol¯¹ = AcH3 =-282.8 kJ mol¹ AcH4-393.5 kJ mol¹

4. i. Using the data at the bottom of the question, calculate the enthalpy of formation of W(CO)6(S). ii. At 298 K, the enthalpies of sublimation of W(CO)6(s) and of W(s) are 75.6 and 849.4 kJ mol¹ respectively. Calculate the mean (W-CO) bond dissociation enthalpy in W(CO)6. The following enthalpies of combustion have been measured at 298 K. W(s) + 1.5 O2(g) → WO3(s) W(CO)6(s) + 4.5 O2(g) → WO3(s) + 6CO2(g) CO(g)+0.5 Oz(g) → CO2(g) C(s) + O2(g) → CO2(g) AcH₁ =-842.9 kJ mol¯¹ AcH2 -2242.7 kJ mol¯¹ = AcH3 =-282.8 kJ mol¹ AcH4-393.5 kJ mol¹

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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4. i. Using the data at the bottom of the question, calculate the enthalpy of formation of W(CO)6(S). ii. At 298 K, the enthalpies of sublimation of W(CO)6(s) and of W(s) are 75.6 and 849.4 kJ mol¹ respectively. Calculate the mean (W-CO) bond dissociation enthalpy in W(CO)6. The following enthalpies of combustion have been measured at 298 K. W(s) + 1.5 O2(g) → WO3(s) W(CO)6(s) + 4.5 O2(g) → WO3(s) + 6CO2(g) CO(g)+0.5 Oz(g) → CO2(g) C(s) + O2(g) → CO2(g) AcH₁ =-842.9 kJ mol¯¹ AcH2 -2242.7 kJ mol¯¹ = AcH3 =-282.8 kJ mol¹ AcH4-393.5 kJ mol¹
Transcribed Image Text:4. i. Using the data at the bottom of the question, calculate the enthalpy of formation of W(CO)6(S). ii. At 298 K, the enthalpies of sublimation of W(CO)6(s) and of W(s) are 75.6 and 849.4 kJ mol¹ respectively. Calculate the mean (W-CO) bond dissociation enthalpy in W(CO)6. The following enthalpies of combustion have been measured at 298 K. W(s) + 1.5 O2(g) → WO3(s) W(CO)6(s) + 4.5 O2(g) → WO3(s) + 6CO2(g) CO(g)+0.5 Oz(g) → CO2(g) C(s) + O2(g) → CO2(g) AcH₁ =-842.9 kJ mol¯¹ AcH2 -2242.7 kJ mol¯¹ = AcH3 =-282.8 kJ mol¹ AcH4-393.5 kJ mol¹
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