Computation.Consider a stick 1.00 m long and its moments of inertia about axes perpendicular to thestick's length and passing through two different points on the stick: first, a point at itscenter and second, a point 24 cm from one end. Calculate the ratio I2/11, the ratio of thesecond moment of inertia to the first.12IVRecord your numerical answer below, assuming three significant figures. Remember to include aas necessary.O SearcheAGE/

We are given a rod with known length. We are given 2 axes. One is through center of mass. Other is…

Answered: Computation. Consider a stick 1.00 m…

Similar questions

A wheel with a moment of inertia of 0.03 kg.m2 is accelerated from rest to 20 rad/s in 5 seconds due to application of a moment of force (torque). When the moment of force is released, the wheel stops in1 min.a) Calculate the moment of friction (torque due to friction).b) Calculate the original moment of force.Hints: The angular acceleration, or deceleration, is determined by the net moment (sum of the moments) acting on the wheel. To start with you don’t know either moment, but the friction moment is the same during both deceleration and acceleration, so you can work that one out first (part a) in the simpler situation (is it during acceleration or deceleration?), then carry it across to the other phase of the movement to work out the accelerating moment (part b). You’ll need to work out the angular acceleration and deceleration in both of the phases.
The triceps muscle in the back of the upper arm extends the forearm. This muscle in a professional boxer exerts a force of 2967 N with an effective perpendicular lever arm of 3.40 cm, producing an angular acceleration of the forearm of 130.0 rad / s². What is the moment of inertia of the boxer's forearm? moment of inertia: kg m? Question Credit: OpenStax College Physics
The triceps muscle in the back of the upper arm extends the forearm. This muscle in a professional boxer exerts a force of 1079 N with an effective perpendicular lever arm of 3.65 cm, producing an angular acceleration of the forearm of 115.0 rad /s^2 What is the moment of inertia of the boxer's forearm?
Computation. Consider a stick 1.00 m long and its moments of inertia about axes perpendicular to the stick's length and passing through two different points on the stick: first, a point at its center and second, a point 13 cm from one end. Calculate the ratio 12/11, the ratio of the second moment of inertia to the first. I 2 1/1/1 = I₁ Record your numerical answer below, assuming three significant figures. Remember to include a "_" as necessary. O Search De
A uniform bar has two small balls glued to its ends. The bar is 1.9 m long and has mass 1.5 kg, while the balls each have mass 0.5 kg and can be treated as point masses. Find the moment of inertia of this combination about an axis perpendicular to the bar and through one of the balls. the answer's unit is. Needs Complete typed solution with 100 % accuracy.
The uniform slender rod has a mass m. If it is released from rest when 0 = 0 determine the angular acceleration of the slender when 0= 90°. L A B Hint: Mass moment of inertia for a slender beam with respect to axis through its center of gravity: T = ML² Where M is the mass of slendel and Lis the length of slender. MacBook Air 888 FA F2 & $. 4 %23 delete 7 8 9 2 3 P Y R W K F G D N M B V command ption ソ
Determine the moment of inertia of a 12.7 kgkg sphere of radius 0.425 mm when the axis of rotation is through its center.
Computation. Consider a stick 1.00 m long and its moments of inertia about axes perpendicular to the stick's length and passing through two different points on the stick: first, a point at its center and second, a point 24 cm from one end. Calculate the ratio I2/11, the ratio of the second moment of inertia to the first. 55 Record your numerical answer below, assuming three significant figures. Remember to include a "_" as necessary. == O Search
Problem 3: Suppose we want to calculate the moment of inertia of a 65.5 kg skater, relative to a vertical axis through their center of mass. Part (a) First calculate the moment of inertia (in kg m2) when the skater has their arms pulled inward by assuming they are cylinder of radius 0.11 m. sin() cos() tan() 7 8 9 HOME cotan() asin() acos() E 4 5 atan() acotan() sinh() 1 3 cosh() tanh() cotanh() END ODegrees O Radians Vol BACKSPACE DEL CLEAR Submit Hint Feedback I give up! Part (b) Now calculate the moment of inertia of the skater (in kg m?) with their arms extended by assuming that each arm is 5% of the mass of their body. Assume the body is a cylinder of the same size, and the arms are 0.825 m long rods extending straight out from the center of their body being rotated at the ends.
y 11 P a aa- X If a = 4 in, determine the moment of inertia about the x-axis located at point P.
A soccer player extends her lower leg in a kicking motion by exerting a force with the muscle above the knee in the front of her leg. Suppose she produces an angular acceleration of 31 rad/s2 and her lower leg has a moment of inertia of 0.95 kg⋅m2 . - What is the force, in newtons, exerted by the muscle if its effective perpendicular lever arm is 1.95 cm?
Question 9 of 10 In Rotational Experiment, a student drew the relation between the moment of inertia of the system I and the square distance R. The value of the moment of inertia of the rod od and the mass ms: OL-200kg.m², m=0.2kg OL=0.02kg.m², m=200g OL=0.02kg.m², m=100kg OL=0.02kg.m², m=100g OL=100kg.m², m=0.2kg G 0.12 0.1 0.08 1(kg.m²) 0.06 0.04 0.02 0 0 0.05 0.1 0.15 0.2 0.25 R²(m²) 03 0.35 04 0.45

SEE MORE QUESTIONS