The triceps muscle in the back of the upper arm extends the forearm. This muscle in a professional boxer exerts a force of 1079 N with an effective perpendicular lever arm of 3.65 cm, producing an angular acceleration of the forearm of 115.0 rad /s^2 What is the moment of inertia of the boxer's forearm?
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The triceps muscle in the back of the upper arm extends the forearm. This muscle in a professional boxer exerts a force of 1079 N with an effective perpendicular lever arm of 3.65 cm, producing an
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- The triceps muscle in the back of the upper arm extends the forearm. This muscle in a professional boxer exerts a force of 1879 N1879 N with an effective perpendicular lever arm of 3.55 cm3.55 cm, producing an angular acceleration of the forearm of 130.0 rad / s2130.0 rad / s2. What is the moment of inertia of the boxer's forearm?A figure skater is spinning with an angular velocity of +10.3 rad/s. She then comes to a stop over a brief period of time. During this time, her angular displacement is +4.97 rad. Determine the time during which she comes to rest.A student sits on a freely rotating stool holding two dumbbells, each of mass 2.93 kg (see figure below). When his arms are extended horizontally (Figure a), the dumbbells are 1,09 m from the axis of rotation and the student rotates with an angular speed of 0.745 rad/s. The moment of inertia of the student plus stool is 2.64 kg m² and is assumed to be constant. The student puls the dumbbells inward horizontally to a position 0.307 m from the rotation axis (Figure b) 1 (a) Find the new anguler speed of the student. rad/s (b) Find the kinetic energy of the rotating system before and after he pulls the dumbbells inward. Koefore Kate"
- The triceps muscle in the back of the upper arm extends the forearm. This muscle in a professional boxer exerts a force of 1559 N with an effective perpendicular lever arm of 3.25 cm, producing an angular acceleration of the forearm of 110.0 rad / s?. What is the moment of inertia of the boxer's forearm? moment of inertia: kg m?A top has a moment of inertia of 11.8 kg-m^2. The top is spinning at 68 rpm. How much rotational kinetic energy (in joules) does the top have?A child is playing with a 2.00 kg spinning toy (yo-yo) consisting of an axle connected to two disks, and a string looped around the axle, as shown below. The toy moves up and down as the toy winds and unwinds the string. It has a moment of inertia I = 2.72 X 10-4 kg-m2. At the time shown below, the toy is rotating with an angular speed w = 29.2 rad/s. The string is wound around the axel, whose radius is 2.50 cm. Find the total kinetic energy (rotational plus translational) of the toy as it moves up the string at that point.
- PLEASE DRAW AN FBD AND ANSWER IT ON A PAPER The figure shown is on a fixed frictionless axle. It has a moment of inertia of I = 50 kg-m2 . The forces acting on the object are F1 = 100 N, F2 = 200 N, and F3 = 250 N acting at different radii R1 =60 cm, R2 = 42 cm, and R3 = 28 cm. Determine the angular acceleration of the object.A figure skater rotating at 50.00 rad/s with arms extended has a moment of inertia of 4.5 kg. m^2. If the arms are pulled in so the moment of inertia decreases to 1.80 kg. m^2, what is the final angular speed? O 17.6 rad/s 12.25 rad/s 0.125 rad/ s 0.81 rad/s 125 rad /sThe angle an airplane propeller makes with the horizontal as a function of time is given by θ=(145rad/s)t+(47.0rad/s2)t2. Estimate the instantaneous angular velocity at t=2.000s by calculating the average angular velocity from t=2.000s to t=2.010s. Calculate the average angular acceleration from t=0.00s to t=1.00s. Calculate the average angular acceleration from t=1.00s to t=2.00s.
- 11.2A soccer player extends her lower leg in a kicking motion by exerting a force with the muscle above the knee in the front of her leg. Suppose she produces an angular acceleration of 31 rad/s2 and her lower leg has a moment of inertia of 0.95 kg⋅m2 . - What is the force, in newtons, exerted by the muscle if its effective perpendicular lever arm is 1.95 cm?A circular disk with a radius of 0.45 m is subject to 2 tangentially applied forces. The disc is fixed such that it will rotate about its center. Both forces produce a torque in the same direction. The mass of the disc is 0.59 kg. The moment of inertia of a disc is I MR? F1 = 2.3 N applied at the outer edge of the disc. %D F2 = 4.3 N applied at a distance of 0.21 from the center of the disc. What is the angular acceleration of the disc?