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R= 1.1 meters M= 286 kg m = 41 kg v = 2.5 m/s Part (a) Calculate the moment of inertia of the merry-go-round, in kg · m2. / Correct! I- 178 Part (b) Immediately before the boy jumps on the merry go round, calculate his angular speed (in radians/second) about the central axis of the merry-go-round. j-מ!2.274Correct Part (c) Immediately after the boy jumps on the merry go round, calculate the angular speed in radians/second of the merry-go-round and boy. w2 = 0.013134 : 13 0.013 - נ" Part (d) The boy then crawls towards the center of the merry-go-round along a radius. What is the angular speed in radians/second of the merry- go-round when the boy is half way between the edge and the center of the merry go round? w3 = 0.0158 Part (e) The boy then crawls to the center of the merry-go-round. What is the angular speed in radians/second of the merry-go-round when the boy is at the center of the merry go round? w4 = 1.0 Part (f) Finally, the boy decides that he has had enough fun. He decides to crawl to the outer edge of the merry-go-round and jump off. Somehow, he manages to jump in such a way that he hits the ground with zero velocity with respect to the ground. What is the angular speed in radians/second of the merry-go-round after the boy jumps off? ws = 0.015| sin() cos() tan() 8 9 HOME cotan() asin() acos() E 1^ 4 5 6 atan acotano sinh0 1 3

R= 1.1 meters M= 286 kg m = 41 kg v = 2.5 m/s Part (a) Calculate the moment of inertia of the merry-go-round, in kg · m2. / Correct! I- 178 Part (b) Immediately before the boy jumps on the merry go round, calculate his angular speed (in radians/second) about the central axis of the merry-go-round. j-מ!2.274Correct Part (c) Immediately after the boy jumps on the merry go round, calculate the angular speed in radians/second of the merry-go-round and boy. w2 = 0.013134 : 13 0.013 - נ" Part (d) The boy then crawls towards the center of the merry-go-round along a radius. What is the angular speed in radians/second of the merry- go-round when the boy is half way between the edge and the center of the merry go round? w3 = 0.0158 Part (e) The boy then crawls to the center of the merry-go-round. What is the angular speed in radians/second of the merry-go-round when the boy is at the center of the merry go round? w4 = 1.0 Part (f) Finally, the boy decides that he has had enough fun. He decides to crawl to the outer edge of the merry-go-round and jump off. Somehow, he manages to jump in such a way that he hits the ground with zero velocity with respect to the ground. What is the angular speed in radians/second of the merry-go-round after the boy jumps off? ws = 0.015| sin() cos() tan() 8 9 HOME cotan() asin() acos() E 1^ 4 5 6 atan acotano sinh0 1 3

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R = 1.1 meters M= 286 kg m = 41 kg v = 2.5 m/s Part (a) Calculate the moment of inertia of the merry-go-round, in kg m². / Correct! I= 178 Part (b) Immediately before the boy jumps on the merry go round, calculate his angular speed (in radians/second) about the central axis of the merry-go-round. / Correct! 01 = 2.27 Part (c) Immediately after the boy jumps on the merry go round, calculate the angular speed in radians/second of the merry-go-round and boy. w2 = 0.013134 w2 = 0.01313 Part (d) The boy then crawls towards the center of the merry-go-round along a radius. What is the angular speed in radians/second of the merry- go-round when the boy is half way between the edge and the center of the merry go round? w3 = 0.0158 回於 is at the center of the merry go round? Part (e) The boy then crawls to the center of the merry-go-round. What is the angular speed in radians/second of the merry-go-round when the boy w4 = 1.0 04 = 1 Part (f) Finally, the boy decides that he has had enough fun. He decides to crawl to the outer edge of the merry-go-round and jump off. Somehow, he manages to jump in such a way that he hits the ground with zero velocity with respect to the ground. What is the angular speed in radians/second of the merry-go-round after the boy jumps off? ws = 0.015| sin() cos() tan() 8 9 HOME cotan() asin() acos() E 4 atan() acotan() sinh() 1 2 3 cosh() tanh() cotanh() END O Degrees O Radians BACKSPACE DEL CLEAR Submit Hint Feedback I give up!
Transcribed Image Text:R = 1.1 meters M= 286 kg m = 41 kg v = 2.5 m/s Part (a) Calculate the moment of inertia of the merry-go-round, in kg m². / Correct! I= 178 Part (b) Immediately before the boy jumps on the merry go round, calculate his angular speed (in radians/second) about the central axis of the merry-go-round. / Correct! 01 = 2.27 Part (c) Immediately after the boy jumps on the merry go round, calculate the angular speed in radians/second of the merry-go-round and boy. w2 = 0.013134 w2 = 0.01313 Part (d) The boy then crawls towards the center of the merry-go-round along a radius. What is the angular speed in radians/second of the merry- go-round when the boy is half way between the edge and the center of the merry go round? w3 = 0.0158 回於 is at the center of the merry go round? Part (e) The boy then crawls to the center of the merry-go-round. What is the angular speed in radians/second of the merry-go-round when the boy w4 = 1.0 04 = 1 Part (f) Finally, the boy decides that he has had enough fun. He decides to crawl to the outer edge of the merry-go-round and jump off. Somehow, he manages to jump in such a way that he hits the ground with zero velocity with respect to the ground. What is the angular speed in radians/second of the merry-go-round after the boy jumps off? ws = 0.015| sin() cos() tan() 8 9 HOME cotan() asin() acos() E 4 atan() acotan() sinh() 1 2 3 cosh() tanh() cotanh() END O Degrees O Radians BACKSPACE DEL CLEAR Submit Hint Feedback I give up!
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