During a very quick stop, a car decelerates at 6.4 m/s2. Assume the forward motion of the car corresponds to a positive direction for the rotation of the tires (and that they do not slip on the pavement). at = 6.4 m/s2 r = 0.26 m ω0 = 91 rad/s a. What is the angular acceleration of its tires in rad/s2, assuming they have a radius of 0.26 m and do not slip on the pavement? b. How many revolutions do the tires make before coming to rest, given their initial angular velocity is 91 rad/s? c. How long does the car take to stop completely in seconds?
Angular speed, acceleration and displacement
Angular acceleration is defined as the rate of change in angular velocity with respect to time. It has both magnitude and direction. So, it is a vector quantity.
Angular Position
Before diving into angular position, one should understand the basics of position and its importance along with usage in day-to-day life. When one talks of position, it’s always relative with respect to some other object. For example, position of earth with respect to sun, position of school with respect to house, etc. Angular position is the rotational analogue of linear position.
During a very quick stop, a car decelerates at 6.4 m/s2. Assume the forward motion of the car corresponds to a positive direction for the rotation of the tires (and that they do not slip on the pavement).
at = 6.4 m/s2
r = 0.26 m
ω0 = 91 rad/s
a. What is the
b. How many revolutions do the tires make before coming to rest, given their initial
c. How long does the car take to stop completely in seconds?
d. What distance does the car travel in this time in meters?
e. What was the car's initial speed in m/s?
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