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Compound A diffuses through a 4 cm long tube and reacts as it diffuses. The equation governing diffusion with reaction along the distance x of the tube (in cm) is given by: d²A D dx2 - kA = 0 At one end of the tube, there is a large source of A at a concentration of 0.1 M. At the other end of the tube there is an adsorbent material that quickly absorbs any A, making the concentration of A zero. If D = 1.5 x 10-6 cm? s-1 and k=6 x 10-6 s-1, i. What is the general solution for the concentration of A as a function of distance in the tube? ii. What would be the concentration of A at lcm distance from the source?

Compound A diffuses through a 4 cm long tube and reacts as it diffuses. The equation governing diffusion with reaction along the distance x of the tube (in cm) is given by: d²A D dx2 - kA = 0 At one end of the tube, there is a large source of A at a concentration of 0.1 M. At the other end of the tube there is an adsorbent material that quickly absorbs any A, making the concentration of A zero. If D = 1.5 x 10-6 cm? s-1 and k=6 x 10-6 s-1, i. What is the general solution for the concentration of A as a function of distance in the tube? ii. What would be the concentration of A at lcm distance from the source?

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Compound A diffuses through a 4 cm long tube and reacts as it diffuses. The equation governing diffusion with reaction along the distance x of the tube (in cm) is given by: d²A D dx2 – kA = 0 At one end of the tube, there is a large source of A at a concentration of 0.1 M. At the other end of the tube there is an adsorbent material that quickly absorbs any A, making the concentration of A zero. If D = 1.5 x 10-6 cm? s-1 and k= 6 x 10-6 s-1, i. What is the general solution for the concentration of A as a function of distance in the tube? ii. What would be the concentration of A at lcm distance from the source?
Transcribed Image Text:Compound A diffuses through a 4 cm long tube and reacts as it diffuses. The equation governing diffusion with reaction along the distance x of the tube (in cm) is given by: d²A D dx2 – kA = 0 At one end of the tube, there is a large source of A at a concentration of 0.1 M. At the other end of the tube there is an adsorbent material that quickly absorbs any A, making the concentration of A zero. If D = 1.5 x 10-6 cm? s-1 and k= 6 x 10-6 s-1, i. What is the general solution for the concentration of A as a function of distance in the tube? ii. What would be the concentration of A at lcm distance from the source?
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