complete the table and calculate the mass defect and binding energy for K39 c)explain the significance of the binding energy of an isotope d) use data to explain why potassium -42 is a beta minus emitter but postassiun -39 can not undergo beta minus decay
complete the table and calculate the mass defect and binding energy for K39 c)explain the significance of the binding energy of an isotope d) use data to explain why potassium -42 is a beta minus emitter but postassiun -39 can not undergo beta minus decay
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Chapter26: Relativity
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B) complete the table and calculate the mass defect and binding energy for K39
c)explain the significance of the binding energy of an isotope
d) use data to explain why potassium -42 is a beta minus emitter but postassiun -39 can not undergo beta minus decay
![Q3: The table shows two isotopes of potassium and two isotopes of calcium.
Type of emission
Mass of neutral atom / u
Number of electrons
Number of protons
Number of neutrons
Total mass/u
Mass defect/ u
Binding energy / J
39K
Stable
38.96371
Mass of the electron = 0.000549 u
Mass of the proton = 1.007276 u
Mass of the neutron = 1.008665 u
42K
ß decay
41.9624
19
19
23
42.34797
0.38557
5.76 x 10-11
39 Ca
ßt decay
38.9707
42 Ca
stable
41.95863
a) Use data about potassium-42 to explain the concept of mass defect.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F1d940493-4f77-460a-8c1e-34ada369b86e%2F300d7d75-8d8b-4209-a474-67db8e7b993b%2F040t1io_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Q3: The table shows two isotopes of potassium and two isotopes of calcium.
Type of emission
Mass of neutral atom / u
Number of electrons
Number of protons
Number of neutrons
Total mass/u
Mass defect/ u
Binding energy / J
39K
Stable
38.96371
Mass of the electron = 0.000549 u
Mass of the proton = 1.007276 u
Mass of the neutron = 1.008665 u
42K
ß decay
41.9624
19
19
23
42.34797
0.38557
5.76 x 10-11
39 Ca
ßt decay
38.9707
42 Ca
stable
41.95863
a) Use data about potassium-42 to explain the concept of mass defect.
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