The purpose of this problem is to show in three ways that the binding energy at the election in a hydrogen atom is negligible compared with the masses of the proton and electron. (a) Calculate the mass equivalent in u of the 13.6−eV binding energy of an electron in a hydrogen atom, and compete this with the mass of the hydrogen atom obtained from Appendix A. (b) Subtract the mass at the proton given in Table 31.2 from the mass at the hydrogen atom given in Appendix A. You will find the difference is equal to the electron’s mass to three digits, implying the binding energy is small in comparison. (c) Take the ratio of the binding energy at the electron (13.6 eV) to the energy equivalent of the electron's mass (0.511 MeV). (d) Discuss how your answers confirm the stated purpose of this problem.
The purpose of this problem is to show in three ways that the binding energy at the election in a hydrogen atom is negligible compared with the masses of the proton and electron. (a) Calculate the mass equivalent in u of the 13.6−eV binding energy of an electron in a hydrogen atom, and compete this with the mass of the hydrogen atom obtained from Appendix A. (b) Subtract the mass at the proton given in Table 31.2 from the mass at the hydrogen atom given in Appendix A. You will find the difference is equal to the electron’s mass to three digits, implying the binding energy is small in comparison. (c) Take the ratio of the binding energy at the electron (13.6 eV) to the energy equivalent of the electron's mass (0.511 MeV). (d) Discuss how your answers confirm the stated purpose of this problem.
The purpose of this problem is to show in three ways that the binding energy at the election in a hydrogen atom is negligible compared with the masses of the proton and electron. (a) Calculate the mass equivalent in u of the 13.6−eV binding energy of an electron in a hydrogen atom, and compete this with the mass of the hydrogen atom obtained from Appendix A. (b) Subtract the mass at the proton given in Table 31.2 from the mass at the hydrogen atom given in Appendix A. You will find the difference is equal to the electron’s mass to three digits, implying the binding energy is small in comparison. (c) Take the ratio of the binding energy at the electron (13.6 eV) to the energy equivalent of the electron's mass (0.511 MeV). (d) Discuss how your answers confirm the stated purpose of this problem.
The binding energy of a hydrogen atom is 13.6 eV.(a) What is the decrease in mass that occurs when a hydrogen atom is formed from a proton and a neutron? Express the result in atomic mass units (u) and in mass percent of hydrogen.(b) What is the decrease in mass that occurs when a helium nucleus is formed from two protons and two neutrons? Express the result in atomic mass units (u) and in percent of the mass of the helium nucleus.(c) Compare your answers to items (a) and (b). Why do we hear that mass "loss" occurs in nuclear reactions but not in chemical reactions (Lavoisier's Law)?
An Erbium-166 nucleus contains 68 protons. The atomic mass of a
neutral Erbium-166 atom is 165.930u, where u = 931.5 MeV/c². In
this question you may use that the mass of a proton is 938.27 MeV/c²,
the mass of a neutron is 939.57 MeV/e² and the mass of an electron
is 0.511 MeV/c².
i. Calculate the nuclear binding energy per nucleon, giving your
answer in units of MeV.
ii. Electrons with an energy of 0.5 GeV are scattered off the nucleus.
Estimate the scattering angle of the first minimum in the resulting
diffraction pattern.
iii. Briefly comment on whether or not you expect this nucleus to be
spherical, and what consequence this has for excited states of
the nucleus in the collective model.
He is 4.001506 u. Find the binding energy of He
2
Given that the mass of a helium nucleus
2
(Given: Mass of proton, m, = 1.007277 u; Mass of neutron, m, = 1.008665 u; 1 u = 931.5 MeV)
O 28 MeV
O 28.3 MeV
O 4.0318 u
O 0.0304 u
Physics for Scientists and Engineers: A Strategic Approach, Vol. 1 (Chs 1-21) (4th Edition)
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