Complete the code to implement the following operations: Complete read_date(): Read an input string representing a date in the format yyyy-mm-dd. Create a date object from the input string. Return the date object. Call read_date() to read four (unique) date objects and store the date objects in a list. Call sorted() to sort the list of date objects, earliest first. Store the sorted dates in a new list. Output the sorted_dates, in the format mm/dd/yy. Hint: Use strftime() to format the date outputs. (See resource below.) Output the number of days between the last two dates in the sorted list as a positive number. Output the date that is 3 weeks from the most recent date in the format "July 4, 1776". Hint: Use timedelta() to set a duration of time for the arithmetic on date objects. (See resources below.) Ex: timedelta(days=50, seconds=27, hours=8, weeks=2) will define a duration of 50 days + 27 seconds + 8 hours + 2 weeks. Output the full name of the day of the week of the earliest day.
Complete the code to implement the following operations: Complete read_date(): Read an input string representing a date in the format yyyy-mm-dd. Create a date object from the input string. Return the date object. Call read_date() to read four (unique) date objects and store the date objects in a list. Call sorted() to sort the list of date objects, earliest first. Store the sorted dates in a new list. Output the sorted_dates, in the format mm/dd/yy. Hint: Use strftime() to format the date outputs. (See resource below.) Output the number of days between the last two dates in the sorted list as a positive number. Output the date that is 3 weeks from the most recent date in the format "July 4, 1776". Hint: Use timedelta() to set a duration of time for the arithmetic on date objects. (See resources below.) Ex: timedelta(days=50, seconds=27, hours=8, weeks=2) will define a duration of 50 days + 27 seconds + 8 hours + 2 weeks. Output the full name of the day of the week of the earliest day.
Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
Problem 1PE
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11.8 LAB: Dates
Complete the code to implement the following operations:
- Complete read_date():
- Read an input string representing a date in the format yyyy-mm-dd.
- Create a date object from the input string.
- Return the date object.
- Call read_date() to read four (unique) date objects and store the date objects in a list.
- Call sorted() to sort the list of date objects, earliest first. Store the sorted dates in a new list.
- Output the sorted_dates, in the format mm/dd/yy.
- Hint: Use strftime() to format the date outputs. (See resource below.)
- Output the number of days between the last two dates in the sorted list as a positive number.
- Output the date that is 3 weeks from the most recent date in the format "July 4, 1776".
- Hint: Use timedelta() to set a duration of time for the arithmetic on date objects. (See resources below.)
Ex: timedelta(days=50, seconds=27, hours=8, weeks=2) will define a duration of 50 days + 27 seconds + 8 hours + 2 weeks.
- Hint: Use timedelta() to set a duration of time for the arithmetic on date objects. (See resources below.)
- Output the full name of the day of the week of the earliest day.
Code I have so far:
from datetime import date,timedelta
def read_date():
inputDate=input()
listDate=inputDate.split("-")
x = date(int(listDate[0]),int(listDate[1]),int(listDate[2]))
return x
DateObject=[]
print()
for i in range(4):
DateObject.append(read_date())
DateObject.sort()
print()
for i in DateObject:
print(i.strftime("%m/%d/%Y"))
print((DateObject[3]-DateObject[2]).days)
d = timedelta(days=21)
t= DateObject[-1]+d
print(t.strftime("%B %d, %Y"))
print(DateObject[0].strftime("%A"))
error I am getting:
it says that for all of my outputs I have two lines before the text in my output:
Input
2022-01-27
2022-07-04
2020-12-31
2022-07-29
Your output starts with
12/31/2020
01/27/2022
07/04/2022
07/29/2022
Expected output starts with
12/31/2020
01/27/2022
07/04/2022
07/29/2022
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