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Computer Networking: A Top-Down Approach (7th Edition)

7th Edition

ISBN:9780133594140

Author:James Kurose, Keith Ross

Publisher:James Kurose, Keith Ross

Chapter1: Computer Networks And The Internet

Section: Chapter Questions

Problem R1RQ: What is the difference between a host and an end system? List several different types of end...

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Related questions

Question

* Ryan Chin

CS 111B Assignment 4

Count Words and display longest word

import java.util.Scanner;

public class Main

{

publicstaticvoid main(String[] args)

{

String phrase;

int numWords;

phrase = inputPhrase();

numWords = analyzePhrase(phrase);

System.out.println("Your phrase has " + numWords + " words in it.");

System.out.println();

}

/**

inputPhrase method

Ask the user to input a phrase, and make sure it is at least 5 characters long.

(Use a loop to make the user input a new phrase if it is too short.)

@return the phrase

// INSERT YOUR CODE HERE

static String inputPhrase()

{

Scanner scan = new Scanner(System.in);

String phrase;

boolean keepSearching;

{

keepSearching = false;

System.out.println("Please enter a phrase all on one line, " + "with just one space separating each word, and no spaces " + "at the beginning or end of the phrase.");

phrase = scan.nextLine();

if(phrase.length()<5)

{

keepSearching = true;

System.out.println("Your phrase must contain at least 5 characters. ");

}

}while(keepSearching);

return phrase;

}

/**

analyzePhrase method

Count the number of words in a given string, and determine its longest word.

Assume the string is well formed and doesn't have leading

or trailing spaces, or multiple spaces in a row.

Return the number of words.

Output the longest word on the screen (console).

@param str string to analyze

@return number of words in str

// INSERT YOUR CODE HERE

staticint analyzePhrase(String phrase)

{

int count =0;

int lastIndex;

String longest = phrase.substring(0, phrase.indexOf(' '));

int ptr1 =0;

int ptr2 =0;

int sizeOfLongest =0;

for(int i=0; i<phrase.length()-1; i++)

{

int size;

if(phrase.charAt(i)==' ')

{

ptr2 = phrase.charAt(i);

count++;

}

size = ptr2 - ptr1;

if(size > sizeOfLongest)

{

longest = phrase.substring(ptr1, ptr2);

ptr1 = ptr2;

}

System.out.println("The longest word in your phrase is " + longest + " with " + longest.length() + " characters.");

return count+1;

}

/* Hints:

To count words and determine their lengths, I recommend you use a for-loop to go

through each character one at a time, using .charAt and then when you see a

space ' ' count the word and set a variable to remember which character number

that was, so you can calculate how long each word is. Use a variable for the

longest word seen so far, and compare each word as you see it, to determine if

it is longer than the longest word seen so far. If so, update that to the

longest word seen so far. Don't forget about the final word, which doesn't

end with a space.

}

/* Sample Output: