Compare trials 1 and 2 where [B] is constant. The rate law can be written as: rate = k[A][B]". rate2 0.090 = 9. rate1 0.010 [A]m 6.0m = 3m [A] m 2.0m
Compare trials 1 and 2 where [B] is constant. The rate law can be written as: rate = k[A][B]". rate2 0.090 = 9. rate1 0.010 [A]m 6.0m = 3m [A] m 2.0m
Chemistry: Matter and Change
1st Edition
ISBN:9780078746376
Author:Dinah Zike, Laurel Dingrando, Nicholas Hainen, Cheryl Wistrom
Publisher:Dinah Zike, Laurel Dingrando, Nicholas Hainen, Cheryl Wistrom
Chapter16: Reaction Rates
Section16.3: Reaction Rate Laws
Problem 26SSC
Related questions
Question
![Compare trials 1 and 2 where [B] is
constant.
The rate law can be written as: rate
= k[A][B]".
rate2
0.090
= 9.
rate1
0.010
[A]m
6.0m
= 3m
[A] m
2.0m](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F98788fff-5d55-4f08-bd33-832b3c76eea7%2F5686d90a-d85a-4312-9e58-a89383bdbded%2Fznhdapj_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Compare trials 1 and 2 where [B] is
constant.
The rate law can be written as: rate
= k[A][B]".
rate2
0.090
= 9.
rate1
0.010
[A]m
6.0m
= 3m
[A] m
2.0m
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