Combustion of glucose (C6H₁2O6) is the main source of energy for animal cells: C6H₁2O6(s) + 60₂(g) → 6CO₂(g) + 6H₂O (1) - AGTx (37 °C) = -2872. kJ rxn One of the most important uses to which this energy is put is the assembly of proteins out of amino acid building blocks. The Gibbs free energy of formation of one peptide bond, joining one amino acid to another, is 21 kJ/mol. Suppose some cells are assembling a certain protein made of 83 amino acids. (Note that the number of peptide bonds in the protein will be one less than the number of amino acids.) Calculate the minimum mass of glucose that must be burned to assemble 250. µmol of this protein. Round your answer to 2 significant digits.

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Combustion of glucose (C6H₁2O6) is the main source of energy for animal cells:
12
C6H₁₂O6(s) + 60₂(g) → 6CO₂(g) + 6H₂O (1)
12
AG (37 °C) = -2872. kJ
rxn
One of the most important uses to which this energy is put is the assembly of proteins out of amino acid building blocks. The Gibbs free energy of formation
of one peptide bond, joining one amino acid to another, is 21 kJ/mol.
Suppose some cells are assembling a certain protein made of 83 amino acids. (Note that the number of peptide bonds in the protein will be one less than the
number of amino acids.) Calculate the minimum mass of glucose that must be burned to assemble 250. µmol of this protein.
Round your answer to 2 significant digits.
Transcribed Image Text:Combustion of glucose (C6H₁2O6) is the main source of energy for animal cells: 12 C6H₁₂O6(s) + 60₂(g) → 6CO₂(g) + 6H₂O (1) 12 AG (37 °C) = -2872. kJ rxn One of the most important uses to which this energy is put is the assembly of proteins out of amino acid building blocks. The Gibbs free energy of formation of one peptide bond, joining one amino acid to another, is 21 kJ/mol. Suppose some cells are assembling a certain protein made of 83 amino acids. (Note that the number of peptide bonds in the protein will be one less than the number of amino acids.) Calculate the minimum mass of glucose that must be burned to assemble 250. µmol of this protein. Round your answer to 2 significant digits.
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