Cold air at 5°C enters a 19.1-cm-diameter 20-m-long isothermal pipe at a velocity of 1.8 m/s and leaves at 45°C. What is the convective heat transfer coefficient (W/m .K)? [p = 1.184 kg/m", c, = 1007 J/kg.K, k= 0.02551 W/m.K, v = 1.562 E-5 , Pr = 0.7296] Assume fully developed flow, if turbulent flow use Dittus-Boelter equation Nu = 0.023 Re Pr

Elements Of Electromagnetics
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Cold air at 5°C enters a 19.1-cm-diameter 20-m-long
isothermal pipe at a velocity of 1.8 m/s and leaves at
45°C. What is the convective heat transfer coefficient
(W/m K)? [p = 1.184 kg/m', c, = 1007 J/kg.K, k= 0.02551
W/m.K, v = 1.562 E-5, Pr = 0.7296] Assume fully
developed flow, if turbulent flow use Dittus-Boelter
equation Nu = 0.023 Re
Pr
Transcribed Image Text:Cold air at 5°C enters a 19.1-cm-diameter 20-m-long isothermal pipe at a velocity of 1.8 m/s and leaves at 45°C. What is the convective heat transfer coefficient (W/m K)? [p = 1.184 kg/m', c, = 1007 J/kg.K, k= 0.02551 W/m.K, v = 1.562 E-5, Pr = 0.7296] Assume fully developed flow, if turbulent flow use Dittus-Boelter equation Nu = 0.023 Re Pr
Expert Solution
Step 1

Given data:

d=19.1 cmL=20 mv=1.8 m/sTi=5°CTe=45°C

Need to determine the convective heat transfer coefficient.

 

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