CO Со, -4.94876985 x 103 kJ/mol н -3.94506117 x 10' kJ/mol 0.39305376802 kJ/mol/K 0.4111337849 kJ/mol/K S G ? -4.94999564 x 10' kJ/mol -3.94623306 x 105 kJ/mol The enthalpy, entropy, and free energy of CO can be computed as follows. First, we define the geometry at the equilibrium geometry, computed in the Enthalpy lesson mol_CO [["C", 0, 0, 0], ["O", 0, 0, 1.13485718]]; mol_CO [["C", 0, 0, 0]. ["O", 0, 0, 1.13485718]] (2.2) Finally, we compute a table of thermodynamic properties for CO including the enthalpy, entropy, and free energy. By default, the command uses a temperature of 298 K > thermo_CO= Thermodynamics(mol_CO, 'DensityFunctional', basis = "cc-pvdz"); J entropy=389.04949897 energy= -2.97355647 108 mol mol pe13100.56264564 mol thermo COtable , heat capacity= 20.81 00 12 14 ,electronic_energy= -2.97388047 108 J (2.3) mol K mol K J enthalpy= -2.97353168 108 J -2.74504846 K, free_energy= -2.97469163 10° mol 0 2.74504846 K mol в (a) What is the computed enthalpy of CO in kJ/mol? (b) What is the computed entropy of CO in kJ/mol/K? (c) What is the computed free energy of CO in kJmol? We can convert the enthalpy, entropy, and free energy from J to kJ using Maple's convert command kJ >H[CO] comnvertthermo_CO[ enthalpy],'unts'.- mol kJ Hco=-297353.16764385 mol (2.4) kJ SICO] convertthermo_CO[entropy],'units', mol K kJ =0.38904950 Sco (2.5) mol K convert > G[CO] thermo_CO[ free_energy],'units','- mol kJ Gco=-297469.16275 197 mol (2.6) Similarly, answer the following questions: (e) Using the entropy of CO in (b) and the precomputed entropy values in Table 1, calculate the change in entropy in the combustion of l mol of CO Using the free energy of CO in (c) and the precomputed free energy values in Table 1, calculate the change in free energy in the combustion of 1 mol of CO. (g) Using the change in enthalpies and entropies and the Gibbs free energy equation, compute the change in free energy in the combustion of 1 mol of CO (h) Do you results for the free energy change in (f) and (g) agree? i Using the change in enthalpies and entropies and the Gibbs free energy equation, estimate the temperature below which the reaction is spontaneous.