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Write the empirical formula for at least four ionic compounds that could be formed from the following iom NH,, PO, Fe*, CH, CO, 0 0.0.... X

Write the empirical formula for at least four ionic compounds that could be formed from the following iom NH,, PO, Fe*, CH, CO, 0 0.0.... X

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
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Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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**Task: Empirical Formulas for Ionic Compounds** **Problem Statement:** Write the empirical formula for at least four ionic compounds that could be formed from the following ions: - \( \text{NH}_4^+ \) - \( \text{PO}_4^{3-} \) - \( \text{Fe}^{3+} \) - \( \text{CH}_3\text{CO}_2^- \) **Solution:** To form ionic compounds, we pair cations (positively charged ions) with anions (negatively charged ions) such that the total positive charge equals the total negative charge. Here are possible combinations: 1. **Ammonium Phosphate (\( \text{(NH}_4\text{)}_3\text{PO}_4 \))** - 3 Ammonium ions (\( \text{NH}_4^+ \)) paired with 1 Phosphate ion (\( \text{PO}_4^{3-} \)) 2. **Iron(III) Acetate (\( \text{Fe(CH}_3\text{CO}_2\text{)}_3 \))** - 1 Iron(III) ion (\( \text{Fe}^{3+} \)) paired with 3 Acetate ions (\( \text{CH}_3\text{CO}_2^- \)) 3. **Iron(III) Phosphate (\( \text{FePO}_4 \))** - 1 Iron(III) ion (\( \text{Fe}^{3+} \)) paired with 1 Phosphate ion (\( \text{PO}_4^{3-} \)) 4. **Ammonium Acetate (\( \text{NH}_4\text{CH}_3\text{CO}_2 \))** - 1 Ammonium ion (\( \text{NH}_4^+ \)) paired with 1 Acetate ion (\( \text{CH}_3\text{CO}_2^- \)) Each formula is balanced such that the total positive and negative charges cancel each other out to form a neutral compound.
Transcribed Image Text:**Task: Empirical Formulas for Ionic Compounds** **Problem Statement:** Write the empirical formula for at least four ionic compounds that could be formed from the following ions: - \( \text{NH}_4^+ \) - \( \text{PO}_4^{3-} \) - \( \text{Fe}^{3+} \) - \( \text{CH}_3\text{CO}_2^- \) **Solution:** To form ionic compounds, we pair cations (positively charged ions) with anions (negatively charged ions) such that the total positive charge equals the total negative charge. Here are possible combinations: 1. **Ammonium Phosphate (\( \text{(NH}_4\text{)}_3\text{PO}_4 \))** - 3 Ammonium ions (\( \text{NH}_4^+ \)) paired with 1 Phosphate ion (\( \text{PO}_4^{3-} \)) 2. **Iron(III) Acetate (\( \text{Fe(CH}_3\text{CO}_2\text{)}_3 \))** - 1 Iron(III) ion (\( \text{Fe}^{3+} \)) paired with 3 Acetate ions (\( \text{CH}_3\text{CO}_2^- \)) 3. **Iron(III) Phosphate (\( \text{FePO}_4 \))** - 1 Iron(III) ion (\( \text{Fe}^{3+} \)) paired with 1 Phosphate ion (\( \text{PO}_4^{3-} \)) 4. **Ammonium Acetate (\( \text{NH}_4\text{CH}_3\text{CO}_2 \))** - 1 Ammonium ion (\( \text{NH}_4^+ \)) paired with 1 Acetate ion (\( \text{CH}_3\text{CO}_2^- \)) Each formula is balanced such that the total positive and negative charges cancel each other out to form a neutral compound.
Expert Solution
Step 1

Empirical formula: it can be defined as the simplest whole number ratio of different atoms in the compound.

Ionic compound:

• Ionic compound composed of cation which is positively charged (+charge) and an anion which is negatively charged (-charge).

• Ionic compound are electrically neutral.

• Ionic compound composed of

1) A metal and a non metal eg. AlCl3

2) A metal and a polyatomic anion eg.  Mg(NO3)2

3) A polyatomic cation and a non metal eg. NH4Br

4) A polyatomic cation and a polyatomic anion eg NH4NO3

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