### Classify the type of elementary step shown below.![Diagram showing a chemical reaction mechanism](url)In the diagram, we observe the following elementary reaction:1. **Reactants:** - The left side features a molecule with a double bond and an adjacent hydrogen (H) and iodine (I) atoms. - A negatively charged nitrogen species, denoted as anion $\ce{N-CH3}$ with lone pairs on nitrogen, is also shown.2. **Mechanism:** - An arrow from the iodine (I) atom to the nitrogen anion ($\ce{N-CH3}$) signifies the iodine atom leaving the molecule as iodide ($\ce{I-}$) and the formation of a double bond in the carbon chain. - Simultaneously, a curved arrow from the carbon-hydrogen bond near the double bond to between carbons adjacent to the double bond indicates hydrogen is being removed, resulting in the formation of $\ce{H2C=CH}$ alkyne in the final product.3. **Products:** - The right side shows the final products after the mechanism: an alkyne and the anion $\ce{N-CH3}$ now bonded to a hydrogen atom ($\ce{NH-CH3}$).### Multiple Choice:A) Bimolecular Elimination B) Nucleophilic Elimination C) Bimolecular Nucleophilic Substitution D) Electrophilic Addition The correct answer here is **A) Bimolecular Elimination**, because the reaction involves the elimination of atoms (hydrogen and iodine) from the substrate to form a double (alkyne) bond, and the rate of reaction depends on the concentration of both the substrate and the base, indicating a bimolecular process.For more detailed explanations and study resources, visit our detailed section on reaction mechanisms. This diagram depicts a reaction mechanism commonly studied in organic chemistry. Here, the reaction involves the transformation of an alkyl group in the presence of a nucleophilic base. Let's break down the components of this diagram:1. **Reaction Mechanism**: - The left side of the diagram shows the starting materials: an alkyl substrate and a base (likely an amine, given the structure). - Curved arrows indicate the flow of electrons during the reaction: - One arrow shows the base abstracting a proton (H) from the alkyl substrate. - Another arrow indicates the formation of a double bond as a result of this proton abstraction. - The right side of the diagram shows the final products: an alkene and the conjugate acid of the base.2. **Options for Reaction Type**: - **A) bimolecular elimination**: This refers to an E2 (bimolecular elimination) mechanism where the removal of a proton and the formation of the double bond occur simultaneously. - **B) nucleophilic elimination**: A pathway involving a nucleophile eliminating a group, typically less common and not fitting the given mechanism well. - **C) bimolecular nucleophilic substitution**: This relates to an SN2 (substitution nucleophilic bimolecular) reaction, which does not fit the given elimination pathway. - **D) electrophilic addition**: This describes addition reactions where an electrophile adds to a compound, not applicable here. - **E) electrophilic elimination**: Involves the elimination of an electrophile, not fitting the present base-induced elimination mechanism.The correct answer to the question regarding the type of reaction depicted in this diagram is option **A) bimolecular elimination**, as it showcases a base-induced simultaneous removal of a proton and formation of a double bond, characteristic of an E2 reaction mechanism.

The following reaction is an elimination reaction and by eliminating leaving group an alkyne is…

Answered: Classify the type of elementary step…

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Chemistry

Classify the type of elementary step shown below. H H. N-CH3 -I H N-CH3 H

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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