Circular Motion A1 Kg bead is confined to move on a vertical circle of radius 2 meters. There is no friction between the bead and the circular track. The bead has a speed of 10 m/s when at the top of the circle at point "A", and the total mechanical energy of the bead is assumed to be constant as it moves around the circle. Assume it takes the bead 0.62 seconds to go counter-clockwise from point "A" to point "B" each cycle. 10 m/s 2m 30° Note: vector directions should be given as the "standard" angle with 0 <0 < 360 degrees Calculate the magnitude of the average velocity (m/s) from "A" to "B" (based on the 0.62 seconds mentioned in the description).

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Circular Motion
A 1 Kg bead is confined to move on a vertical circle of radius 2 meters. There is no
friction between the bead and the circular track. The bead has a speed of 10 m/s
when at the top of the circle at point "A", and the total mechanical energy of the
bead is assumed to be constant as it moves around the circle.
Assume it takes the bead 0.62 seconds to go counter-clockwise from point "A" to
point "B" each cycle.
10 m/s
2 m
1
Note: vector directions should be given as the "standard" angle with
0<0 < 360 degrees
30°
Calculate the magnitude of the average velocity (m/s) from "A" to "B" (based on the
0.62 seconds mentioned in the description).
Transcribed Image Text:Circular Motion A 1 Kg bead is confined to move on a vertical circle of radius 2 meters. There is no friction between the bead and the circular track. The bead has a speed of 10 m/s when at the top of the circle at point "A", and the total mechanical energy of the bead is assumed to be constant as it moves around the circle. Assume it takes the bead 0.62 seconds to go counter-clockwise from point "A" to point "B" each cycle. 10 m/s 2 m 1 Note: vector directions should be given as the "standard" angle with 0<0 < 360 degrees 30° Calculate the magnitude of the average velocity (m/s) from "A" to "B" (based on the 0.62 seconds mentioned in the description).
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