**Text Transcription and Diagram Description for Educational Website**---**Diagram Description:**The diagram illustrates a simple pulley system. On the left side, a crate with mass \( M \) is connected to a rope. The rope passes over a pulley and is pulled down by a person on the right side. The movement in the system indicates that the crate is "going up" while the person is "pulling down" on the rope. The pulley is labeled as a "light pulley."**Problem Statement:***A person is lifting a crate (mass = m) using a simple pulley. The crate rises at constant speed. Calculate the work done by the person pulling the rope straight down, when the box moves distance d upward.***Parameters:**- Mass \( m = 53 \, \text{kg} \)- Distance \( d = 2.7 \, \text{m} \)*Calculate the work in joules (J).***Answer Options:**- \( \text{A: } 1.404 \times 10^3 \)- \( \text{B: } 1.867 \times 10^3 \)- \( \text{C: } 2.483 \times 10^3 \)- \( \text{D: } 3.303 \times 10^3 \)- \( \text{E: } 4.393 \times 10^3 \)- \( \text{F: } 5.842 \times 10^3 \)- \( \text{G: } 7.770 \times 10^3 \)- \( \text{H: } 1.033 \times 10^4 \)---**Educational Explanation:**When a crate is lifted using a pulley at a constant speed, the work done by the person is calculated using the formula for gravitational work: \[ \text{Work} = m \cdot g \cdot d \]where \( g \) is the acceleration due to gravity (\( 9.8 \, \text{m/s}^2 \)). This formula results from the force exerted against gravity to lift the mass over a vertical distance \( d \). Choosing the correct answer involves calculating this expression based on given parameters.

Mass = m = 53 kg Distance = d = 2.7 m Work done by person = W = ?

1 lige pulley going up polling down IN on is lifting a crate (mass = m) using a . The crate rises at constant speed. Ca Ork done by the person pulling the rop nt down, when the box moves distanc d. cers: ]

1 lige pulley going up polling down IN on is lifting a crate (mass = m) using a . The crate rises at constant speed. Ca Ork done by the person pulling the rop nt down, when the box moves distanc d. cers: ]

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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Question

**Text Transcription and Diagram Description for Educational Website**

---

**Diagram Description:**

The diagram illustrates a simple pulley system. On the left side, a crate with mass \( M \) is connected to a rope. The rope passes over a pulley and is pulled down by a person on the right side. The movement in the system indicates that the crate is "going up" while the person is "pulling down" on the rope. The pulley is labeled as a "light pulley."

**Problem Statement:**

*A person is lifting a crate (mass = m) using a simple pulley. The crate rises at constant speed. Calculate the work done by the person pulling the rope straight down, when the box moves distance d upward.*

**Parameters:**

- Mass \( m = 53 \, \text{kg} \)
- Distance \( d = 2.7 \, \text{m} \)

*Calculate the work in joules (J).*

**Answer Options:**

- \( \text{A: } 1.404 \times 10^3 \)
- \( \text{B: } 1.867 \times 10^3 \)
- \( \text{C: } 2.483 \times 10^3 \)
- \( \text{D: } 3.303 \times 10^3 \)
- \( \text{E: } 4.393 \times 10^3 \)
- \( \text{F: } 5.842 \times 10^3 \)
- \( \text{G: } 7.770 \times 10^3 \)
- \( \text{H: } 1.033 \times 10^4 \)

---

**Educational Explanation:**

When a crate is lifted using a pulley at a constant speed, the work done by the person is calculated using the formula for gravitational work:

\[ \text{Work} = m \cdot g \cdot d \]

where \( g \) is the acceleration due to gravity (\( 9.8 \, \text{m/s}^2 \)). This formula results from the force exerted against gravity to lift the mass over a vertical distance \( d \). Choosing the correct answer involves calculating this expression based on given parameters.

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